c++ - 不接受输入

Question

我想写一个只取奇数的程序，如果你输入0它会输出加法和平均值，而不取任何偶数值来求平均值和加法。我坚持不让它采用偶数..到目前为止，这是我的代码:

    int num = 0;
    int addition = 0;
    int numberOfInputs = 0;

    cout << "Enter your numbers (only odd numbers), the program will continue asking for numbers until you input 0.." << endl;

    for (; ;) {

    cin >> num;
    numberOfInputs++;
    addition = addition + num;

    if (num % 2 != 0) {
     //my issue is with this part
        cout << "ignored" << endl;
    }

    if (num == 0) {
        cout << "Addition: " << addition << endl;
        cout << "Average: " << addition / numberOfInputs << endl;
        }
} 

Answer 1

您的代码的解决方案:

由于以下原因，您的代码无法正常工作:

问题 1:您添加输入数字而不检查它是否为偶数

问题 2:如果想跳过，那么您的条件在循环内应该如下所示:

if (num%2==0) {
cout << "ignored:" <<num << endl;
continue;
} 

为了解决您的问题，我已将您的程序更新如下:

#include <iostream>
#include <string>
using namespace std;

int main()
{
  int num = 0;
int addition = 0;
int numberOfInputs = 0;

cout << "Enter your numbers (only odd numbers), the program will continue asking for numbers until you input 0.." << endl;

for (; ;) {

cin>> num;

 if (num%2==0) {
    cout << "ignored:" <<num << endl;
    continue;
}
numberOfInputs++;
addition = addition + num;



if (num == 0) {
    cout << "Addition: " << addition << endl;
    cout << "Average: " << addition / numberOfInputs << endl;
    break;
    }
 } 

}