c++ - 在C++中融化POC

Question

我听说了Meltdown漏洞，并阅读了paper，这很困难，因为我不是母语人士，但是我决定制作一个概念验证的小型c++程序，如下所示，我想知道造成这种情况的原因代码不起作用。
我已经在AMD FX 8350八核和Intel I3处理器上对其进行了测试

/*In this code I wanted to make a PoC for the Meltdown flaw (https://meltdownattack.com/)*/
#include "stdafx.h"
#include <stdlib.h>
#include <iostream>
#include <chrono>

int secretvar = 15;     //This is our "unreadable" var wich we "cannot" read but we will have the value exposed via cache attack
int x = rand() % 100;   //Used later, importent that it's random

int main()
{   
    int arr[1000];                  //We setup our array
    for (int i = 0; i < 100; ++i) { //Fill it with random values
        arr[i] = rand() % 10 + 1;
    };

    if (x == 4) {                       //Here I want to trigger the Out-of-Order execution so that the cpu executes the code below th if case
        int c = arr[secretvar];         //before it really checks if x is actually 4. And with this, the CPU would put the cached variable "c" into
                                        //its cache.
    };

/*At this point we dont know th value of secretvar but we know that the CPU has cached some index with the
exact value of secretvar.Therefore we can now iterate over the array and how long it takes the cpu to acess the
diffrent array indexes.The cpu will be faster at acessing one specific element because it is taken from cache 
and not from the memory.This index is the value of secretvar.*/

    double lowest_val = 500;
    int    lowest_index = 0;

    for (int i = 0; i < 100; i++) {
        auto start = std::chrono::high_resolution_clock::now(); //start timer
        arr[i];                                                 //acess array
        auto finish = std::chrono::high_resolution_clock::now();//end timer
        std::chrono::duration<double> elapsed = finish - start;//calculate needed time
        double e = elapsed.count();
        if (e < lowest_val) {
            lowest_val = e;
            lowest_index = i;
        }
        std::cout << i << " : " << e << " s\n"; //show it to the screen
    }
    std::cout <<  lowest_index << "Was acessed fastest "<< " with a time of  "<< lowest_val << "ms" << std::endl;
    system("pause");
    return 0;
}

Answer 1

好的，因此我意识到，如果我用汇编器对其进行编程，则此测试会更加准确。接下来我会尝试，但是在那之前我必须学习一些东西。我认为问题已经解决，但是仍然欢迎您提出有关c++程序的建议。
谢谢您的帮助