c++ - 如何从过滤后的数据创建笛卡尔积范围？

Question

我正在尝试从更小的范围创建笛卡尔积范围。我认为 ranges::v3::view::cartesian_product 会起作用，但不知为何它不起作用。

如果我尝试直接使用容器创建笛卡尔积，我没有问题。以下编译:

#include <vector>
#include <range/v3/view/cartesian_product.hpp>

int main() {
    std::vector<int> data1{1,5,2,7,6,3,4,8,9,0};
    std::vector<int> data2{1,5,2,7,6,3,4,8,9,0};
    auto range = ranges::v3::view::cartesian_product(data1, data2);
}

但是，一旦我开始使用过滤器:

#include <vector>
#include <range/v3/view/cartesian_product.hpp>
#include <range/v3/view/filter.hpp>

int main() {
    std::vector<int> data1{1,5,2,7,6,3,4,8,9,0};
    std::vector<int> data2{1,5,2,7,6,3,4,8,9,0};
    auto range = ranges::v3::view::cartesian_product(
            data1 | ranges::v3::view::filter([](int v) { return v%2; }),
            data2);
}

我遇到了大量难以破译的编译错误，首先是:

In file included from contrib/range/v3/view/cartesian_product.hpp:21:0,
                 from cartesian-err.cpp:2:
contrib/range/v3/range_concepts.hpp: In instantiation of ‘class ranges::v3::cartesian_product_view<ranges::v3::remove_if_view<ranges::v3::iterator_range<__gnu_cxx::__normal_iterator<int*, std::vector<int, std::allocator<int> > >, __gnu_cxx::__normal_iterator<int*, std::vector<int, std::allocator<int> > > >, ranges::v3::logical_negate_<main()::<lambda(int)> > >, ranges::v3::iterator_range<__gnu_cxx::__normal_iterator<int*, std::vector<int, std::allocator<int> > >, __gnu_cxx::__normal_iterator<int*, std::vector<int, std::allocator<int> > > > >’:
cartesian-err.cpp:10:18:   required from here
contrib/range/v3/range_concepts.hpp:78:50: error: no match for call to ‘(const ranges::v3::_begin_::fn) (const ranges::v3::remove_if_view<ranges::v3::iterator_range<__gnu_cxx::__normal_iterator<int*, std::vector<int> >, __gnu_cxx::__normal_iterator<int*, std::vector<int> > >, ranges::v3::logical_negate_<main()::<lambda(int)> > >&)’
                 using iterator_t = decltype(begin(std::declval<T &>()));
                                             ~~~~~^~~~~~~~~~~~~~~~~~~~~

我该如何绕过它？

附言有没有关于 ranges-v3 库的一些好的文档？我找不到任何东西，我觉得我在黑暗中行走......

Answer 1

无论是否有错误，都可以按照 https://github.com/ericniebler/range-v3/issues/173 中的建议通过手动实现来绕过 cartesian_product .

额外的好处是，您可以更好地控制迭代顺序，如果过滤器函数开销很大，这可能会对性能产生影响。

在上述情况下，可以这样实现(为简洁起见缩短了输入 vector ):

#include <vector>
#include <iostream>
#include <range/v3/view/for_each.hpp>
#include <range/v3/view/filter.hpp>

int main() {
    std::vector<int> data1{1,5,2,7,6};
    std::vector<int> data2{1,5,2,7,6};
    auto range =
            data1
            | ranges::v3::view::filter([](int v) { return v%2; })
            | ranges::v3::view::for_each([&](int v) {
                return data2 | ranges::v3::view::for_each([v](int v2) {
                    return ranges::v3::yield(std::make_pair(v,v2));
                });
            });
    for (auto&& pair : range) {
        std::cout << "[" << pair.first << "," << pair.second << "]\n";
    }
    return 0;
}

给出预期的输出:

[1,1]
[1,5]
[1,2]
[1,7]
[1,6]
[5,1]
[5,5]
[5,2]
[5,7]
[5,6]
[7,1]
[7,5]
[7,2]
[7,7]
[7,6]