c++ - 一种缩短声明的方法

Question

我有这样的东西:

 template<class Key,
                 class Value,
                 class Compare_p = Compare<ByKey>,
                 template<class,class> class Insert_p = NoOverride,
                 template<class> class FailureSignal_p = ThrowOnFailure,
                 class AllocFactor_p = AllocFactorScientific<>,
                 class Alloc = Allocator<FailureSignal_p>
                >
        class Map : private Map_Base<Implementation> //Implementation is a Link with identical  
//params to Map
        {
        public:  
//I've tried to use typedef here but it's too late
            typedef LinkImplementation<Pair<Key,Value>,Compare_p,Insert_p,FailureSignal_p,AllocFactor_p,Alloc> Implementation;
    };

所以最大的问题是:有没有办法缩短这个声明(LinkImplementation<>)？

Answer 1

也许可以像这样为 map 参数创建一个模板“结构”:

template <class Key, ...  blablabla > struct MapParams{typedef Key key_t;typedef Value value_t;..................};

然后使用这个“结构”作为一个单一的模板参数用于 Map 和 Map_Base 模板？