c++ - 减去无符号并得到有符号

Question

我可以这样转换吗？

int clockOffset;

clockOffset=((int64_t)Time_1_delayed-Time_1-Time_2_delayed+Time_2)/2;

其中所有时间变量都是 uint。

我想在 clockOffset 中得到签名结果。

Answer 1

这是您可以在 C 中执行的操作(假设 int 和 unsigned int 比 long long 短):

#include <limits.h>

...
  unsigned int Time_1_delayed, Time_1, Time_2_delayed, Time_2;
...
  long long diff = ((long long)Time_1_delayed - Time_1 - Time_2_delayed + Time_2) / 2;
  int clockOffset;

  if (diff < INT_MIN || diff > INT_MAX)
    HandleTheError();

  clockOffset = diff;
...