c++ - 如何对卡诺图中的单元格进行分类

Question

我在卡诺图的分类上遇到了一些问题，我不知道如何定义卡诺表的各种情况，

如果我使用连续的“if”和“else”语句，我认为这是非常低级的编程，我想要一些本身已知的算法，或者使用较少的“if”和“else”语句这里有一些卡诺图的分类示例:

我的程序必须知道这两个“1”属于一个类别，并且将被归类为两个我怎样才能将这个灌输到我的程序中，我怎样才能实现这个分类这是我的两个变量卡诺图的代码:

int num_var;        // stores the number of variables entered by user
int squ_4[4];       // variable used for a 1-D array for the 4 square Karnaugh map
int a,b,c;          // variables for entering and checking values in Karnaugh map squares
char var_name[10];  // character string array

strcpy(var_name,"ABCDRSXYZ");   // character string for variable name

printf("\nThis program works out a Boolean function for a 2,3 and 4 variable Karnaugh map.\n\n");

cout << "Enter number of Karnaugh map variables (2,3 or 4) required: ";
cin >> num_var;
do
{
    if(num_var>4)
    {
        printf("\n Sorry, you have chosen too many variables \n");
        printf("\n Please enter 2,3 or 4 variables: ");
        cin >> num_var;
    }
    if(num_var<2)
    {
        printf("\n Sorry, not enough variables chosen \n");
        printf("\n Please enter 2,3 or 4 variables: ");
        cin >> num_var;
    }
}while(num_var>4 || num_var<2);

do
{
    printf("\nVariables are: %c %c \n",var_name[4],var_name[5]);    // output variable names

    printf("\n Please enter value in Karnaugh map square and press RETURN \n")

    for(a=0;a<4;a++)
    {
        printf("\nEnter 1 or 0 into square %d: ",a);
        cin >> squ_4[a];    // store value into array

        while(squ_4[a]!=0 && squ_4[a]!=1)
        {
            printf("\n Value entered in Karnaugh map square %d, was not 1 or 0 \n",a);
            printf("\nPlease enter 1 or 0 into square %d: ",a);
            cin >> squ_4[a];
        }
    }
    printf("\nYour Karnaugh map is: \n\n\t\t     %c'%c \n\t\t   %c'%d %d\n\t\t   %c %d %d \n",var_name[5],var_name[5],var_name[4],squ_4[0],squ_4[1],var_name[4],squ_4[2],squ_4[3]);


    if(squ_4[0]==0 && squ_4[1]==0 && squ_4[2]==0 && squ_4[3]==0)
    {
        printf("\nThere is no function from the Karnaugh map\n\n");
        return 0;
    }
    printf("\nThe Boolean function is: \n\n ");

    if(squ_4[0]==1)
    {
        printf("%c'%c' ",var_name[4],var_name[5]);
        if(squ_4[1]==1 || squ_4[2]==1 || squ_4[3]==1)
        {
            printf("+ ");
        }
    }
    if(squ_4[1]==1)
    {
        printf("%c'%c ",var_name[4],var_name[5]);
        if(squ_4[2]==1 || squ_4[3]==1)
        {
            printf("+ ");
        }
    }
    if(squ_4[2]==1)
    {
        printf("%c%c' ",var_name[4],var_name[5]);
        if(squ_4[3]==1)
        {
            printf("+ ");
        }
    }
    if(squ_4[3]==1)
    {
        printf("%c%c ",var_name[4],var_name[5]);
    }

    cout << "\n\n\n\n";
}while(num_var==2);

Answer 1

将他们的答案存储在某个变量中并使用循环比较结果。