c++ - 创建具有正确边的无向图

Question

您好，我正在创建 100 个图表用于在 dijkstra 算法中进行测试。我检查以确保连接的两个随机生成的节点号不相同。但是我不明白如何检查一对是否已经存在，以便两个节点之间出现多个边缘。如何防止两个节点之间出现两条边？

void mapDataGenerator(int start, int end, int iterations,
                        int *pathCount, int *weightCount, int *timeCount)
{
int nodeCount = rand() % 8128 + 64;
edgeListTemplate edgeList(nodeCount);
//cout << "The node count is: " << nodeCount;
int n = 0;
list<vertex_v> path;
vector<weight_w> min_distance;
vector<vertex_v> previous;


while (n != nodeCount)
{

    int nodeNumb = (rand() % nodeCount); // Generates a possible node 1 
    int nodeDest = (rand() % nodeCount); // Generates a possible node 2

    //cout << "The node connection 1 is: " << nodeNumb << endl;
    //cout << "The node connection 2 is: " << nodeDest << endl;
    int node_weight = rand() % 5 + 1; // Generate random weight of node

    //cout << "The node weight is: " << node_weight << endl;

    // Create adjacency list
    if (nodeNumb != nodeDest) // if the random nodes generated are not same
    {
        edgeList[nodeNumb].push_back(node(nodeDest, node_weight));
        // For undirected graph create opposite connection back 
        edgeList[nodeDest].push_back(node(nodeNumb, node_weight));
        ++n;
    }
  }

Answer 1

您可以简单地使用映射/集合数据结构来跟踪已经存在的边。精确映射对将完成这项工作。

代码

// map declaration
map<pair<int, int>, bool> M;

if (nodeNumb != nodeDest && !M.count(make_pair(nodeNumb, nodeDest))) // if the random nodes generated are not same
{
     // Marking the pair of edges
     M[make_pair(nodeNumb, nodeDest)] = true;
     edgeList[nodeNumb].push_back(node(nodeDest, node_weight));
     // For undirected graph create opposite connection back 
     edgeList[nodeDest].push_back(node(nodeNumb, node_weight));
     ++n;
 }