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C++ 窗口捕获输出与所述窗口的大小不同

转载 作者:塔克拉玛干 更新时间:2023-11-03 07:05:52 25 4
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我有一个用 C++ 编写的简短程序,用于从这个 BlueStacks 仿真器窗口捕获像素,然后我将使用 OpenCV 操纵像素,然后根据一些决定发送鼠标输入 (win32api)。我在 Visual Studio Enterprise 2017 中工作。

唯一的问题是,与整个窗口相比,该函数似乎捕获了较小的像素区域。

这是一个示例图片。原始窗口在左侧,镜像输出在右侧。

example

我该如何解决这个问题?我已经在我的项目设置中启用了高 DPI 感知,不知道除了将随机魔数(Magic Number)添加到函数中之外还需要采取哪些其他步骤。

我已经用 Python 完成了这个程序,但我想用 C++ 重做这个以提高性能。

Here's a video (warning: noise). And another one.

这是我当前的代码:

#include "stdafx.h"
#include "opencv2/imgproc.hpp"
#include "opencv2/highgui.hpp"
#include <Windows.h>
#include <iostream>

using namespace std;
using namespace cv;

Mat hwnd2mat(HWND hwnd);

int main(int argc, char **argv)
{
printf("Hello, world!\n");
Sleep(1000);

HWND hwndDesktop;

hwndDesktop = GetForegroundWindow();
// namedWindow("output", WINDOW_NORMAL);
int key = 0;
Mat src;

while (key != 27)
{
src = hwnd2mat(hwndDesktop);
// you can do some image processing here
imshow("output", src);
key = waitKey(1); // you can change wait time
}

}

Mat hwnd2mat(HWND hwnd)
{
HDC hwindowDC, hwindowCompatibleDC;

int height, width, srcheight, srcwidth;
HBITMAP hbwindow;
Mat src;
BITMAPINFOHEADER bi;

hwindowDC = GetDC(hwnd);
hwindowCompatibleDC = CreateCompatibleDC(hwindowDC);
SetStretchBltMode(hwindowCompatibleDC, COLORONCOLOR);

RECT windowsize; // get the height and width of the screen
GetClientRect(hwnd, &windowsize);

srcheight = windowsize.bottom;
srcwidth = windowsize.right;
height = windowsize.bottom / 1; //change this to whatever size you want to resize to
width = windowsize.right / 1;

src.create(height, width, CV_8UC4);

// create a bitmap
hbwindow = CreateCompatibleBitmap(hwindowDC, width, height);
bi.biSize = sizeof(BITMAPINFOHEADER); //http://msdn.microsoft.com/en-us/library/windows/window/dd183402%28v=vs.85%29.aspx
bi.biWidth = width;
bi.biHeight = -height; //this is the line that makes it draw upside down or not
bi.biPlanes = 1;
bi.biBitCount = 32;
bi.biCompression = BI_RGB;
bi.biSizeImage = 0;
bi.biXPelsPerMeter = 0;
bi.biYPelsPerMeter = 0;
bi.biClrUsed = 0;
bi.biClrImportant = 0;

// use the previously created device context with the bitmap
SelectObject(hwindowCompatibleDC, hbwindow);
// copy from the window device context to the bitmap device context
StretchBlt(hwindowCompatibleDC, 0, 0, width, height, hwindowDC, 0, 0, srcwidth, srcheight, SRCCOPY); //change SRCCOPY to NOTSRCCOPY for wacky colors !
GetDIBits(hwindowCompatibleDC, hbwindow, 0, height, src.data, (BITMAPINFO *)&bi, DIB_RGB_COLORS); //copy from hwindowCompatibleDC to hbwindow

// avoid memory leak
DeleteObject(hbwindow);
DeleteDC(hwindowCompatibleDC);
ReleaseDC(hwnd, hwindowDC);

return src;
}

最佳答案

拉伸(stretch)是由于 DPI 缩放。您自己的程序不支持 DPI,而其他程序似乎支持 DPI。让您的程序了解 DPI 的最简单方法是在程序开始时调用 SetProcessDPIAware();

另外请注意,调用 GetDIBits 时,不应在设备上下文中选择 HBITMAP 句柄。您可以将代码重写为

SetProcessDPIAware();
...

Mat hwnd2mat(HWND hwnd)
{
RECT rc;
GetClientRect(hwnd, &rc);
int width = rc.right;
int height = rc.bottom;

Mat src;
src.create(height, width, CV_8UC4);

HDC hdc = GetDC(hwnd);
HDC memdc = CreateCompatibleDC(hdc);
HBITMAP hbitmap = CreateCompatibleBitmap(hdc, width, height);
HBITMAP oldbmp = (HBITMAP)SelectObject(memdc, hbitmap);

BitBlt(memdc, 0, 0, width, height, hdc, 0, 0, SRCCOPY);
SelectObject(memdc, oldbmp);

BITMAPINFOHEADER bi = { sizeof(BITMAPINFOHEADER), width, -height, 1, 32, BI_RGB };
GetDIBits(hdc, hbitmap, 0, height, src.data, (BITMAPINFO*)&bi, DIB_RGB_COLORS);

DeleteObject(hbitmap);
DeleteDC(memdc);
ReleaseDC(hwnd, hdc);

return src;
}

此代码仅适用于 native Win32 程序。对于 Chrome、WPF、Qt 应用程序等其他程序,这将显示空白屏幕。您需要截取桌面窗口的屏幕截图。

关于C++ 窗口捕获输出与所述窗口的大小不同,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50395294/

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