c++ - 如何让std::thread在执行完其成员函数后自动删除对象

Question

我想实现一个 cmmand 类，它在另一个线程中做一些工作，我不想让用户手动删除该对象。我的 command 像这样上课:

class Cmd {
 public:
  void excute() {
    std::cout << "thread begins" << std::endl;
    std::this_thread::sleep_for(std::chrono::seconds(2));  // do some work
    std::cout << "thread ends" << std::endl;
  }

  void run() {
    // I want std::unique_ptr to delete 'this' after work is done,but does't work
    std::thread td(&Cmd::excute, std::unique_ptr<Cmd>(this));
    td.detach();
  }

  // test if this object is still alive
  void ok() { std::cout << "OK" << std::endl; }
};

我是这样使用的:

int main() {
  Cmd *p = new Cmd();
  p->run();

  // waiting for cmd thread ends
  std::this_thread::sleep_for(std::chrono::seconds(3));

  p->ok();  // I thought p was deleted but not

  return 0;
}

如评论中所述，在 cmd 线程完成后该对象仍然存在，我想知道如何实现这种功能。

编辑

cmd 的用户不知道cmd 什么时候结束，所以流动的用例会导致 UB。

std::unique_ptr<Cmd> up(new Cmd);  // or just Cmd c;
up->run();
// cmd will be deleted after out of scope but cmd::excute may still need it

关闭

我测试的时候弄错了，实际上对象是在线程结束后被删除的。下面的测试加一个成员变量int i会更清楚。

#include <functional>
#include <iostream>
#include <stack>
#include <thread>

using namespace std;

class Cmd {
 public:
  ~Cmd() { std::cout << "destructor" << std::endl; }

  void excute() {
    std::cout << i << " thread begins" << std::endl;
    std::this_thread::sleep_for(std::chrono::seconds(2));  // do some work
    std::cout << i << " thread ends" << std::endl;
  }

  void run() {
    // I want std::unique_ptr to delete 'this' after work is done,but it seems
    // not working
    std::thread td(&Cmd::excute, std::unique_ptr<Cmd>(this));
    td.detach();
  }

  // test if this object is still alive
  void ok() { std::cout << i << " OK" << std::endl; }

  int i;
};

int main() {
  Cmd *p = new Cmd();
  p->i = 10;
  p->run();

  // waiting for cmd thread ends
  std::this_thread::sleep_for(std::chrono::seconds(3));

  p->ok();  // I thought p was deleted but not

  return 0;
}

flowwing 输出证明对象已被删除。

10 thread begins
10 thread ends
destructor
-572662307 OK

但正如一些好心人所建议的那样，这不是一个好的设计，请尽可能避免。

Answer 1

您可以使用 std::future 而不是线程向国家发出信号。然后，您可以等待任务完成，也可以完全忽略 future 。

#include <future>
#include <chrono>
#include <mutex>
#include <iostream>

class Cmd {
public:
    std::future<void> run() {
        std::lock_guard<std::mutex> lock(startMutex);
        if (started) {
            throw std::logic_error("already started");
        }
        started = true;

        // Take copies here, so that it doesn't matter if Cmd is destroyed
        int i_ = i;
        return std::async(std::launch::async, [i_]() {
            std::this_thread::sleep_for(std::chrono::seconds(2));
            std::cout << i_ << std::endl;
        });
    }

    int i = 0;

private:
    std::mutex startMutex;
    bool started = false;
};

int main() {
    auto p = std::make_unique<Cmd>();
    p->i = 10;
    auto f = p->run();
    p.reset();

    // Do some other work

    // Wait for the task to finish (or use f.get() if there is no need to
    // do some other work while waiting)
    if (f.valid()) {
        std::future_status operation;
        do {
            // Do some other work

            operation = f.wait_for(std::chrono::milliseconds(1));
        } while (operation != std::future_status::ready);
    }
}