c++ - 在 Enter 键处拆​​分字符串

Question

我正在从编辑框中获取文本，我希望通过回车键分隔每个名称，例如下面带有 NULL 字符的字符串。

    char *names = "Name1\0Name2\0Name3\0Name4\0Name5";

    while(*names)
    {
        names += strlen(names)+1;
    }

你会如何对回车键做同样的事情(即用/r/n 分隔)？你能不使用 std::string 类来做到这一点吗？

Answer 1

使用字符串:

while (*names)
{
    char *next = strstr(names, "\r\n");
    if (next != NULL)
    {
        // If you want to use the key, the length is
        size_t len = next - names;

        // do something with a string here.  The string is not 0 terminated
        // so you need to use only 'len' bytes.  How you do this depends on
        // your need.

        // Have names point to the first character after the \r\n
        names = next + 2;
    }
    else
    {
        // do something with name here.  This version is 0 terminated
        // so it's easy to use

        // Have names point to the terminating \0
        names += strlen(names);
    } 
}

需要注意的是，此代码还修复了代码中的一个错误。您的字符串以单个\0 终止，因此最后一次迭代的名称将指向您的字符串之后的第一个字节。要修复现有代码，您需要将名称的值更改为:

// The algorithm needs two \0's at the end (one so the final
// strlen will work and the second so that the while loop will
// terminate).  Add one explicitly and allow the compiler to
// add a second one.
char *names = "Name1\0Name2\0Name3\0Name4\0Name5\0";