c++ - 将 C++ builder 6 项目转换为 C++ builder 2010

Question

我有一个用 c++ builder 6 编写的简单项目。它是关于加密 RSA 算法的。想要转换为 c++ builder 2010，但它给出了错误

例如主工程源码

//---------------------------------------------------------------------------

#include <vcl.h>
#pragma hdrstop

#include "UTForm.h"
#include "UTRSA.h"
//---------------------------------------------------------------------------
#pragma package(smart_init)
#pragma resource "*.dfm"
TForm1 *Form1;
//---------------------------------------------------------------------------
__fastcall TForm1::TForm1(TComponent* Owner)
        : TForm(Owner)
{
randomize();
}
//---------------------------------------------------------------------------
void __fastcall TForm1::Button1Click(TObject *Sender)
{
TRSA a(Edit4->Text.ToInt());

char* tmp = a.KeyModul;
Edit1->Text = AnsiString(tmp);
tmp = a.OpenKey;
Edit2->Text = AnsiString(tmp);
tmp = a.SecretKey;
Edit3->Text = AnsiString(tmp);
}
//---------------------------------------------------------------------------
void __fastcall TForm1::Button2Click(TObject *Sender)
{
TNumber n(Edit1->Text.c_str());
TNumber e(Edit2->Text.c_str());
TNumber d(Edit3->Text.c_str());

THexString text;
text.AsCharString = Edit5->Text;

if (Edit3->Text != "")
  {
  TRSA a(n,e,d,Edit4->Text.ToInt());
  a.PlainText = text;
  Edit6->Text = a.CryptedText.AsHexString;
  }
else
  {
  TRSA a(n,e,Edit4->Text.ToInt());
  a.PlainText = text;
  Edit6->Text = a.CryptedText.AsHexString;
  }
}

//---------------------------------------------------------------------------
void __fastcall TForm1::Button4Click(TObject *Sender)
{
TNumber n(Edit1->Text.c_str());
TNumber e(Edit2->Text.c_str());
TNumber d(Edit3->Text.c_str());

THexString text;
text.AsHexString = Edit6->Text;

if (Edit3->Text != "")
  {
  TRSA a(n,e,d,Edit4->Text.ToInt());
  a.CryptedText = text;
  Edit8->Text = a.PlainText.AsCharString;
  }
else
  {
  TRSA a(n,e,Edit4->Text.ToInt());
  a.CryptedText = text;
  Edit8->Text = a.PlainText.AsCharString;
  }
}
//---------------------------------------------------------------------------

错误是:

Build
  Checking project dependencies...
  Compiling RSA.cbproj (Debug configuration)
  [BCC32 Warning] UTHexString.cpp(92): W8012 Comparing signed and unsigned values
  [BCC32 Warning] UTHexString.cpp(92): W8012 Comparing signed and unsigned values
  [BCC32 Warning] UTForm.cpp(29): W8057 Parameter 'Sender' is never used
  [BCC32 Error] UTForm.cpp(33): E2285 Could not find a match for 'TNumber::TNumber(wchar_t *)'
  [BCC32 Error] UTForm.cpp(34): E2285 Could not find a match for 'TNumber::TNumber(wchar_t *)'
  [BCC32 Error] UTForm.cpp(35): E2285 Could not find a match for 'TNumber::TNumber(wchar_t *)'
  [BCC32 Warning] UTForm.cpp(52): W8057 Parameter 'Sender' is never used
  [BCC32 Error] UTForm.cpp(57): E2285 Could not find a match for 'TNumber::TNumber(wchar_t *)'
  [BCC32 Error] UTForm.cpp(58): E2285 Could not find a match for 'TNumber::TNumber(wchar_t *)'
  [BCC32 Error] UTForm.cpp(59): E2285 Could not find a match for 'TNumber::TNumber(wchar_t *)'
  [BCC32 Warning] UTForm.cpp(76): W8057 Parameter 'Sender' is never used
  Failed
  Elapsed time: 00:00:01.5
Project Import
  Upgrading project "D:\SOFTS\DELPHI and C++ Builder 2009\Cryptography\RSA\RSA\RSA.bpr"
    Reading "D:\SOFTS\DELPHI and C++ Builder 2009\Cryptography\RSA\RSA\RSA.bpr"
    Upgraded to "D:\SOFTS\DELPHI and C++ Builder 2009\Cryptography\RSA\RSA\RSA.cbproj"

我认为 C++ Builder 2010 具有默认的 unicode 支持，这就是为什么或者我错了？当我查看 TNumber 构造函数时，它具有以下内容:

//---------------------------------------------------------------------------
#ifndef UTNumberH
#define UTNumberH
//---------------------------------------------------------------------------
#include <assert.h>
#include <iostream.h>
#include <iomanip.h>
#include <string.h>
#include <ctype.h>
#include <limits.h>
#include <math.h>

class TNumber
{
private:
       TNumber   multdigit(int) const;
       TNumber   mult10(int) const;

       char     *vlstr;                          
       int       vlen;                           
       int       vlsign;                         

public:

                 TNumber(const char* = NULL);    
                 TNumber(int);                   
                 TNumber(const TNumber &);       
                ~TNumber();                      

                 operator int() const;
                 operator long() const;
                 operator double() const;
                 operator char*() const;

  const TNumber& operator=(const TNumber&);

     TNumber operator - () const;
     TNumber operator ++ ();
     TNumber operator ++ (int);
     TNumber operator -- ();
     TNumber operator -- (int);

         TNumber operator += (const TNumber &);
     TNumber operator -= (const TNumber &);
     TNumber operator *= (const TNumber &);
     TNumber operator /= (const TNumber &);
     TNumber operator %= (const TNumber &);

  friend TNumber operator + (const TNumber &, const TNumber &);
  friend TNumber operator - (const TNumber &, const TNumber &);
  friend TNumber operator * (const TNumber &, const TNumber &);
  friend TNumber operator / (const TNumber &, const TNumber &);
  friend TNumber operator % (const TNumber &, const TNumber &);

  friend int     operator == (const TNumber &, const TNumber &);
  friend int     operator != (const TNumber &, const TNumber &);
  friend int     operator < (const TNumber &, const TNumber &);
  friend int     operator <= (const TNumber &, const TNumber &);
  friend int     operator > (const TNumber &, const TNumber &);
  friend int     operator >= (const TNumber &, const TNumber &);

         char*   strrev(char *s) const;
  friend TNumber abs(const TNumber &);
  friend TNumber sqrt(const TNumber &);
  friend TNumber pow(const TNumber &, const TNumber &);
  friend double  div(const TNumber &, const TNumber &);

  friend ostream & operator << (ostream &, const TNumber &);
  friend istream & operator >> (istream &, TNumber &);

  friend TNumber rnd(const TNumber& from, const TNumber& to);
};

const TNumber zero = TNumber("0");
const TNumber one  = TNumber("1");
const TNumber two  = TNumber("2");

TNumber eae(TNumber u, TNumber v);             

#endif

我哪里错了？

另外找到附加的c++ builder 6项目!

Answer 1

你是对的。 UnicodeString 是大多数字符串在 2010 年的默认设置。由于 Text 属性很可能是其中之一，因此编译的最安全方法是使用某些东西转换回来像下面这样:

TNumber n( AnsiString( Edit1->Text ).c_str() );

更新:

根据评论，我会澄清一下答案。答案是假设代码仍然只需要 ANSi 数据。否则，正如 David M. 指出的那样，更好的解决方案是更改底层 TNumber 类以处理 UnicodeString(即 wchar_t)。