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c++ - Boost::spirit 从非终端获取值(value)

转载 作者:塔克拉玛干 更新时间:2023-11-03 06:49:07 55 4
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我有这个,在我的 boost::spirit 语法中;

paren = (qi::token(LEFT_PAREN) >> character >> qi::token(RIGHT_PAREN)) [ build_paren ]
;
character = qi::token(CHARACTER) [ build_character]
;

这些被定义为;

qi::rule<Iterator> paren;
qi::rule<Iterator, char> character;

函数build_paren,具有以下原型(prototype)(通过编译器转换错误找到);

void build_paren(boost::fusion::vector2<boost::iterator_range<__gnu_cxx::__normal_iterator<char*, std::basic_string<char>>>, boost::iterator_range<__gnu_cxx::__normal_iterator<char*, std::basic_string<char>>>> v)

这里的vector,持有两个字符串,分别是"(\0"")\0",这是我所期望的,但是我如何得到char 字符匹配?

真的,我想要的 build_paran 函数原型(prototype)是;

void build_paren(std::string left_paren, char character, std::string right_paren)

或者,同样,但是 char 参数作为列表中的最后一个。

最佳答案

你不必那么努力:)

Spirit 具有自动属性传播。实际上,我想说这是它的主要卖点。所以你可以:

char parsed_char;
bool ok = qi::phrase_parse(f,l, '(' >> qi::char_("0-9") >> ')', qi::space, parsed_char);

这将简单地绑定(bind) char_公开属性 属性引用 ( parsed_char ) 的解析器组件传递到variadic 解析 API ( phrase_parse )。

下面是一个概括性的演示,展示了您可以通过多种方式来影响具体暴露的内容。解析器指令记录了确切暴露的内容,例如here, for the '%' list parser .

对于您的具体问题,您只想:

qi::rule<Iterator, char()> character;
qi::rule<Iterator, char()> parenthesized;

character = qi::char_("0-9a-z_"); // or qi::alnum, qi::graph, qi::alpha etc...
parenthesized = '(' >> character >> ')';

Note importantly, you need to say qi::rule<Iterator, char()> instead of qi::rule<Iterator, char>!

演示

查看 Live on Coliru :

#include <boost/spirit/include/qi.hpp>
#include <cassert>

namespace qi = boost::spirit::qi;

template<typename ParseExpr, typename... Attr>
void test(const std::string& input, const ParseExpr& p, Attr&... attrs)
{
auto f = input.begin(),
l = input.end();

bool ok = qi::phrase_parse(f,l, p, qi::space, attrs...);

if (!ok)
std::cerr << "parse failed at: '" << std::string(f,l) << "'\n";

if (f!=l)
std::cerr << "trailing unparsed: '" << std::string(f,l) << "'\n";
}

int main()
{
char parsed_char1, parsed_char2;
int parsed_int;
std::string parsed_str;

test("( 0 )", // input
'(' >> qi::char_("0-9") >> ')', // parser/grammar
parsed_char1 // output
);
assert(parsed_char1 == '0');

test("( q 123 )",
'(' >> qi::graph >> qi::int_ >> ')',
parsed_char1,
parsed_int);
assert(parsed_char1 == 'q');
assert(parsed_int == 123);

// parsing strings: with the skipper
test("( hello world )",
'(' >> *~qi::char_(")") >> ')',
parsed_str = "");
assert(parsed_str == "helloworld");

// parsing strings: qi::char_ exposes the char
test("( hello world )",
qi::char_('(') >> *~qi::char_(")") >> qi::char_(')'),
parsed_char1, parsed_str = "", parsed_char2);
assert(parsed_char1 == '(');
assert(parsed_str == "helloworld");
assert(parsed_char2 == ')');

// parsing strings: qi::char_ exposes the char, chars get 'combined' into attribute
test("( hello world )",
qi::char_('(') >> *~qi::char_(")") >> qi::char_(')'),
parsed_str = "");
assert(parsed_str == "(helloworld)");

// parsing strings: as a lexeme
test("( hello world )",
'(' >> qi::lexeme [ *~qi::char_(")") ] >> ')',
parsed_str = "");
assert(parsed_str == "hello world ");

// parsing strings: as bigger lexeme
test("( hello world )",
qi::lexeme [ '(' >> *~qi::char_(")") >> ')' ],
parsed_str = "");
assert(parsed_str == " hello world ");

// parsing anything as "raw" - exposes an iterator pair, but still 'converts' to a string!
test("( hello 42 false )",
qi::raw [ '(' >> qi::lexeme[*qi::graph] >> qi::int_ >> qi::bool_ >> ')' ],
parsed_str = "");
assert(parsed_str == "( hello 42 false )");

// note: this would fail to parse, because with the skipper, *qi::graph would eat "42 false )" as well:
std::cout << "next parse should fail:\n";
test("( hello 42 false )", qi::raw [ '(' >> *qi::graph >> qi::int_ >> qi::bool_ >> ')' ]);
}

关于c++ - Boost::spirit 从非终端获取值(value),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18453814/

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