arrays - 从 moSTLy 线性递增数组中删除异常值

Question

给定一个线性递增的数组，但是

• 可能会遗漏一些数字
• 可能会有一些意想不到的数字，

您将如何构建算法以从数组中删除所有离群值？

可能的数组示例:

1,2,3,4,1,1,1,100,5,6,7

1,2,4,100,5,6,7

1,2,4,100,101,5,6,7,300

2,3,4,5,6,7,300

在上面的所有示例中，您应该能够知道数组应该是 1-7 或 2-7。

一些现实生活中的示例数组:

1, 2, 295, 296, 297, 4, 5, 6, 8, 9, 10, 11, 12, 13, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 5, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 6, 4, 6, 6, 3, 4, 6, 6, 6, 5, 6, 6, 6, 4, 5, 6, 3, 6, 6, 6, 6, 6, 6, 6, 5, 6, 6, 6, 6, 6, 4, 6, 3, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 3, 4, 6, 6, 6, 6, 6, 6, 5, 6, 6, 6, 3, 3, 6, 6, 6, 3, 6, 6, 4, 4, 6, 6, 6, 6, 6, 3, 6, 6, 6, 3, 6, 4, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 3, 6, 6, 3, 6, 6, 6, 6, 6, 6, 5, 6, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 3, 6, 6, 6, 6, 6, 6, 15, 18, 20, 21, 22, 23, 24, 27, 28, 30, 31, 32, 33, 34, 35, 36, 37

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 26, 712, 383, 114, 118, 225, 304, 323, 349, 357, 550, 556, 590, 649, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 51

我想出的一个解决方案是过滤掉所有大于 N(=5？) 大于先前有效值的值，以及所有小于先前有效值的值。

const filterOutliers = (someArray) => {
  let previousValidValue = null;
  return someArray.filter((x, index) => {
    //Assume the first value is valid - although this assumption might not always be true.
    if(!previousValidValue) {
      previousValidValue = x;
      return true;
    }
    // if the number is less than the previous valid value, remove it
    if(x < previousValidValue) {
      return false;
    }
    // if the number is more than 5 greater than the last valid value, remove it
    if(x > previousValidValue + 5) {
      return false;
    }
    previousValidValue = x;
    return true;
  })
}

潜在相关链接:Javascript: remove outlier from an array?

Answer 1

您的异常数据值似乎确实有一个恒定的增量。因此，计算增量，采用模式并保持跟随此增量的值序列(到合适的公差)。