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c++ - 标准 :out_of_range in mergesort

转载 作者:塔克拉玛干 更新时间:2023-11-03 06:32:26 27 4
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首先我不得不说我是算法和 C++ 方面的新手。在 vim 中编写此代码后,当我调试此 c++ 代码时,我遇到了 error:std:out_of_range 并且我不知道错误在哪里。所以我在这里,如果能得到你的帮助,我将非常感激。谢谢

#include <iostream>
#include <cstdio>
#include <ctime>
#include <cmath>
#include <vector>
#include <iterator>
#include <algorithm>
using namespace std;
void merge(vector<int> &a, int first, int mid, int last)
{
a.resize(last - first + 1);
int n1 = mid - first + 1;
int n2 = last - mid;
vector<int> larray(n1, 0);
vector<int> rarray(n2, 0);
for (int i = 0; i != n1; ++i)
larray.at(i) = a.at(first + i);
for (int i = 0; i != n2; ++i)
rarray.at(i) = a.at(mid + 1 + i);
int i = 0;
int j = 0;
int k = 0;
while (i < n1 && j < n2)
{
if (larray.at(k) <= rarray.at(i))
a[k++] = larray[i++];
else
a[k++] = rarray[j++];
}
while (i < n1)
a[k++] = larray[i++];
while (j < n2)
a[k++] = rarray[j++];
}

void MegerSort(vector<int> &a, int first, int last)
{
if (first < last)
{
int mid = (first + last) / 2;
MegerSort(a, first, mid );
MegerSort(a, mid + 1, last);
merge(a, first, mid, last);
}
}

int main()
{
vector<int> array;
srand(unsigned(time(0)));
for (int i = 0; i != 10; ++i)
array.push_back(rand() % 10);
for (vector<int>::iterator it = array.begin(); it != array.end(); ++it)
cout<<*it<<" ";
cout<<endl;
MegerSort(array, 0, 9);
for (vector<int>::iterator it = array.begin(); it != array.end(); ++it)
cout<<*it<<" ";
return 0;
}

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