php - 谷歌 API OAuth 2.0 CURL 返回 "Required parameter is missing: grant_type"

Question

我正在尝试为 Web 服务器应用程序实现 Google 的 OAuth 2.0 身份验证。

我可以从 Google 获取代码，但是当我发回此代码以尝试获取访问 token 时，它总是给我错误“缺少必需的参数:grant_type。错误 400”，即使 grant_type 存在。

此外，如果我将内容长度指定为 0 以外的任何值，它会引发其他错误。

这是执行此 curl 帖子的代码:

$url = 'https://accounts.google.com/o/oauth2/token';
$ch = curl_init($url);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);  
curl_setopt($ch, CURLOPT_FAILONERROR, false);  
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, 'POST'); 

curl_setopt($ch, CURLOPT_HTTPHEADER, array(
    'Content-Type: application/x-www-form-urlencoded',
    'Content-length: 0'
));

curl_setopt($ch, CURLOPT_POSTFIELDS, array( 
    'code='. urlencode($code),
    'client_id=' . urlencode($clientID),
    'client_secret=' . urlencode($clientSecret),
    'redirect_uri=http%3A%2F%2Flocalhost%2Fexperiments%2FnewGALogin.php',
    'grant_type=authorization_code'
)); 

Answer 1

尝试

curl_setopt($ch, CURLOPT_POSTFIELDS, array( 
    'code' => $code,
    'client_id' => $clientID,
    'client_secret' => $clientSecret,
    'redirect_uri' => 'http%3A%2F%2Flocalhost%2Fexperiments%2FnewGALogin.php',
    'grant_type' => 'authorization_code'
)); 

或

curl_setopt($ch, CURLOPT_POSTFIELDS,
    'code=' . urlencode($code) . '&' .
    'client_id=' . urlencode($clientID) . '&' .
    'client_secret=' . urlencode($clientSecret) . '&' .
    'redirect_uri=http%3A%2F%2Flocalhost%2Fexperiments%2FnewGALogin.php' . '&' .
    'grant_type=authorization_code'
);