php - 仅回显 foreach 中的内容一次

Question

我正在尝试回显 foreach 中的内容一次。目前，当用户填写表格时，会为每条跳过的记录显示消息。如果有 35 条记录被跳过，我将收到 35 条消息，因为 foreach。我想避免这种情况，并且能够为整个结果页面只显示一个回显。我怎样才能做到这一点？我想我可能必须在 foreach 之外执行此操作，但我不知道如何将其从 foreach 中取出。

foreach($allcourses as $course)
{
    if(Auth::LoggedIn())
    {
       if(Auth::$userinfo->rank == 'Student')
       {
           if($course->aircraft == '1')
           {
               echo '<div class="msg-red">Some lessons could not be found, because you may not be entitled to view/book them at this stage of your course.</div><br/>';
               continue; 
           }
           if($course->aircraft == '2')
           {
               echo '<div class="msg-red">Some lessons could not be found, because you may not be entitled to view/book them at this stage of your course.</div><br/>';
               continue; 
           }
        }
    }
}

Answer 1

假设您必须维护该对象的结构，如果 $course->aircraft == 1 然后相应地回显，您可以只进行 bool 值更新:

$found = false;
foreach($allcourses as $course)
{
    if(Auth::LoggedIn())
    {
       if(Auth::$userinfo->rank == 'Student')
       {

           if($course->aircraft == '1')
           {
               $found = true;
           }
        }
    }
}
if($found)
{
    echo '<div class="msg-red">Some lessons could not be found, because you may not be entitled to view/book them at this stage of your course.</div><br/>';
}