php - 如何在 PHP5 : $this->foo->bar->baz() 中链接对象

Question

如何在 PHP5 类中创建链接对象？示例:

$myclass->foo->bar->baz();
$this->foo->bar->baz();
Not: $myclass->foo()->bar()->baz();

另请参阅:
http://www.talkphp.com/advanced-php-programming/1163-php5-method-chaining.html

Answer 1

实际上这个问题是模棱两可的......对我来说这个@Geo 的回答是正确的。

你 (@Anti) 说的可能是 composition

这是我的例子:

<?php
class Greeting {
    private $what;
    private $who;


    public function say($what) {
        $this->what = $what;
        return $this;
    }

    public function to($who) {
        $this->who = $who;
        return $this;
    }

    public function __toString() {
        return sprintf("%s %s\n", $this->what, $this->who);
    }

}

$greeting = new Greeting();
echo $greeting->say('hola')->to('gabriel'); // will print: hola gabriel

?>