php - 如何在 PHP 中将对象转换(转换)为没有类名前缀的数组？

Question

如何在 PHP 中将对象转换(转换)为没有类名前缀的数组？

class Teste{

    private $a;
    private $b;

    function __construct($a, $b) {
        $this->a = $a;
        $this->b = $b;
    }

}

var_dump((array)(new Teste('foo','bar')));

结果:

array
  '�Teste�a' => string 'foo' (length=3)
  '�Teste�b' => string 'bar' (length=3)

预期:

array (
a => 'foo'
b => 'bar' )

Answer 1

来自manual :

If an object is converted to an array, the result is an array whose elements are the object's properties. The keys are the member variable names, with a few notable exceptions: integer properties are unaccessible; private variables have the class name prepended to the variable name; protected variables have a '*' prepended to the variable name. These prepended values have null bytes on either side. This can result in some unexpected behaviour:

因此，您可以像这样解决这个问题:

$temp = (array)(new Teste('foo','bar'));
$array = array();
foreach ($temp as $k => $v) {
  $k = preg_match('/^\x00(?:.*?)\x00(.+)/', $k, $matches) ? $matches[1] : $k;
  $array[$k] = $v;
}
var_dump($array);

没有办法控制/禁用这种行为，这似乎很奇怪，因为没有碰撞的风险。