javascript - jQuery AJAX 文件上传错误500

Question

所以我正在尝试使用 JQuery 的 AJAX 进行文件上传，但它一直给我错误 500。

$(function() {
    $( 'form' ).submit
    (
        function()
        {
            $.ajax({
                type: 'POST',
                url: 'photochallenge/submit.php',
                data: new FormData(this),
                processData: false,
                contentType: false,
                success: function(data) {
                    Materialize.toast(data, 4000);
                }
            });
            return false;
        }
    );
});

我也在使用这个 PHP 代码来处理文件上传:

<?php
$target_dir = "uploads/";
$target_file = null;
$uploadOk = 1;
$response = "Please choose an image";
// Check if image file is a actual image or fake image
if(isset($_POST["pic"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        $uploadOk = 1;
    } else {
        $response = "File is not an image.";
        $uploadOk = 0;
    }


    // Check file size
    if ($uploadOk == 1 && $_FILES["fileToUpload"]["size"] > 500000) {
        $response = "Sorry, your file is too large.";
        $uploadOk = 0;
    }

    // Check if $uploadOk is set to 0 by an error
    if ($uploadOk == 0) {

    // if everything is ok, try to upload file
    } else {
        //find target file
        $found = false
        $tmp = 0
        while(!$found)  {
            $target_file = $target_dir . $tmp . ".png";
            if(file_exists($target_file))   {
                $tmp = $tmp + 1;
            }   else    {
                $found = true;
            }
        }

        if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
            $response = "Thank you for your submission!";
            shell_exec("python log.py ".$_POST["firstname"]." ".$_POST["lastname"]." ".$target_file);
        } else {
            $response = "Sorry, there was an error uploading your file.";
        }
    }
}

echo $response;
?>

不幸的是，我无法发布实际问题所在的链接，但希望这段代码足以帮助解决问题。如果需要任何其他详细信息，请随时告诉我。

Answer 1

如果您没有使用“.htaccess”，问题可能出在 shell_exec 中，如果您使用的是 fast-cgi，则可能会导致应用程序崩溃。

注释此行并执行您的脚本:

shell_exec("python log.py ".$_POST["firstname"]." ".$_POST["lastname"]." ".$target_file);

在 PHP 中使用注释:

//shell_exec("python log.py ".$_POST["firstname"]." ".$_POST["lastname"]." ".$target_file);