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php - 无法使用 'foreach' 命令加载图库图像

转载 作者:塔克拉玛干 更新时间:2023-11-03 05:45:27 26 4
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我整理了以下脚本,允许用户在保存的原始文件夹结构中查看他们上传的图像。

更新代码

        <?php session_start(); 

$_SESSION['username']=$_POST['username'];
$_SESSION['locationid']=$_POST['locationid'];

?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<?php
//This variable specifies relative path to the folder, where the gallery with uploaded files is located.
$galleryPath = 'UploadedFiles/' . $_SESSION['username'] . '/' . $_SESSION['locationid'] . '/';

//let's DEBUG the above assignment
if (!is_dir($galleryPath)) { die("No folder exists at $galleryPath!"); }

$absGalleryPath = realpath($galleryPath);

//let's DEBUG this one too
if (!is_dir($absGalleryPath)) { die("No folder exists at $absGalleryPath!"); }

$descriptions = new DOMDocument('1.0');

// DEBUG: let's check for the XML while we're at it
//if (!file_exists($absGalleryPath.'files.xml')) { die("No XML found at $absGalleryPath"."files.xml"); }
$descriptions->load($absGalleryPath . '/' . 'files.xml');


$items = array();

for ($i = 0; $i < $descriptions->documentElement->childNodes->length; $i++) {
$xmlFile = $descriptions->documentElement->childNodes->item($i);
$path = $xmlFile->getAttribute('name');
$path = explode('/', $path);

$t = &$items;
for ($j = 0; $j < count($path); $j++) {
if (empty($t[$path[$j]])) {
$t[$path[$j]] = array();
}
$t = &$t[$path[$j]];
}
$t['/src/'] = $xmlFile->getAttribute('source');
$t['description'] = $xmlFile->getAttribute('description');
$t['size'] = $xmlFile->getAttribute('size');
}

$basePath = empty($_GET['path']) ? '' : $_GET['path'];
if ($basePath) {
$basePath = explode('/', $basePath);
for ($j = 0; $j < count($basePath); $j++) {
$items = &$items[$basePath[$j]];
}
}

$files = array();
$dirs = array();


function urlpartencode(&$item, $index) {
$item = rawurlencode($item);
}

foreach ($items as $key => $value) {
if (isset($value['/src/'])) {
$value['/src/'] = explode('/', $value['/src/']);
array_walk($value['/src/'], 'urlpartencode');
$value['/src/'] = implode('/', $value['/src/']);
$files[] = array(
'name' => $key,
'src' => $value['/src/'],
'description' => htmlentities($value['description'], ENT_COMPAT, 'UTF-8'),
'size' => htmlentities($value['size'], ENT_COMPAT, 'UTF-8')
);
} else {
$dirs[] = $key;
}
}

$basePath = empty($_GET['path']) ? '' : $_GET['path'];
$up = dirname($basePath);
if ($up == '.') {
$up = '';
}

sort($files);
sort($dirs);
?>
<head>
<title>View Image Folders</title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link href="Styles/style.css" rel="stylesheet" type="text/css" />
<script src="Libraries/jquery/jquery-1.4.3.min.js" type="text/javascript"></script>
<style type="text/css">
<!--
.style1 {
font-size: 14px;
margin-top: 5px;
margin-right: -50px;
}

-->
</style>
<body style="font-family: Calibri; color: #505050; margin-right: 160px; margin-left: -180px;">
<div align="right" class="style1"> <a href = "index.php" /> Add Images <a/> &rarr; <a href = "javascript:document.imagefolders.submit()"> View All Images </a> </div>
<form id="imagefolders" name="imagefolders" class="page" action="gallery.php" method="post" enctype="application/x-www-form-urlencoded">
<div id="container">
</div>
<div id="center">
<div class="aB">
<div class="aB-B">
<?php if ('Uploaded files' != $current['title']) :?>
<?php endif;?>
<div class="demo">
<input name="username" type="hidden" id="username" value="IRHM73" />
<input name="locationid" type="hidden" id="locationid" value="1" />
<div class="inner">
<div class="container">
<div class="gallery">
<table class="gallery-link-table" cellpadding="0" cellspacing="0">
<thead>
<tr class="head">
<th class="col-name">
Name
</th>
<th class="col-size">
Size
</th>
<th class="col-description">
Description
</th>
</tr>
</thead>

<tbody>
<tr class="directory odd">
<td class="col-name">
<a href="?path=<?php echo rawurlencode($up); ?>">..</a>
</td>
<td class="col-size">
</td>
<td class="col-description">
</td>
</tr>
<?php $i = 1; ?>

<?php foreach ($dirs as $dir) : ?>
<tr class="directory <?php $i++; echo ($i % 2 == 0 ? 'even' : 'odd'); ?>">
<td><a href="?path=<?php echo rawurlencode(($basePath ? $basePath . '/' : '') . $dir); ?>"><?php echo htmlentities($dir, ENT_COMPAT, 'UTF-8'); ?></a></td>
<td>Folder</td>
<td></td>
</tr>
<?php endforeach; ?>

<?php foreach ($files as $file) : ?>
<tr class="<?php $i++; echo ($i % 2 == 0 ? 'even' : 'odd'); ?>">
<td><a target="_blank" href="<?php echo $galleryPath . $file['src']; ?>"><?php echo htmlentities($file['name'], ENT_COMPAT, 'UTF-8'); ?></a></td>
<td><?php echo htmlentities($file['size'], ENT_COMPAT, 'UTF-8'); ?></td>
<td><?php echo htmlentities($file['description'], ENT_COMPAT, 'UTF-8'); ?></td>
</tr>
<?php endforeach; ?>
</tbody>
</table>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</form>
</body>
</html>

我可以正确显示文件夹,但是当我单击文件夹以深入查看单个图像时,我收到以下错误:

警告:DOMDocument::load() [domdocument.load]:I/O 警告:加载外部实体“/homepages/2/d333603417/htdocs/development/UploadedFiles/files.xml”失败/homepages/2/d333603417/htdocs/development/imagefolders.php 第 25 行警告:为/homepages/2/d333603417/htdocs/development/imagefolders.php 第 65 行中的 foreach() 提供的参数无效

第 25 行是这一行 $descriptions->load($absGalleryPath . '/' . 'files.xml');第 65 行是这样的:foreach ($items as $key => $value) {`

我的初始脚本没有使用 session 变量,我没有遇到任何问题。但是我现在需要包括这些,所以我确信它们与 foreach 命令之间存在冲突。我已经做了相当多的研究,看看是否有其他人遇到过类似的问题,但找不到任何东西。

我只是想知道是否有人可以看看这个并让我知道我哪里错了。

非常感谢和问候

最佳答案

错误 1

Warning: DOMDocument::load() [domdocument.load]: I/O warning : failed to load external entity "/homepages/2/d333603417/htdocs/development/UploadedFiles/files.xml"

问题的根源是 $descriptions->load($absGalleryPath . '/' . 'files.xml');

尝试加载您不确定文件是否存在或可读的文件是不好的做法

像这样更好,确保你能捕捉到异常

$file = $absGalleryPath . '/' . 'files.xml' ;
if(!is_readable($file) || !file_exists($file))
{
throw new Exception("Missing XML File");
}

错误2

Warning: Invalid argument supplied for foreach() in /homepages/2/d333603417/htdocs/development/imagefolders.php on line 65

一个。由于您无法加载第一个 xml 文档...尝试继续该过程将导致此错误

B. foreach ($items as $key => $value) { 所以它会在填充或不填充的地方独立运行

C.太多的 Referencing 会使你的代码更难理解和调试......

结论

我认为你应该发布 files.xml 的内容你会惊讶于人们会想出创新的解决方案和有效的代码

关于php - 无法使用 'foreach' 命令加载图库图像,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10226504/

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