Java，位 vector

Question

我必须编写一个简单的方法，它接受一个索引并将该索引处的“位”从 0 切换到 1。我在为此编写按位运算符时遇到问题。我知道这很简单，但我做不到。下面是该方法的样子。提前致谢!

/** 
 * 32-bit data initialized to all zeros. Here is what you will be using to represent
 * the Bit Vector.
 */

private int bits;

/** You may not add any more fields to this class other than the given one. */

/**
 * Sets the bit (sets to 1) pointed to by index.
 * @param index index of which bit to set.
 *        0 for the least significant bit (right most bit).
 *        31 for the most significant bit.
 */
public void set(int index)
{
            //It is here where I can not figure it out. Thank you!
    System.out.println(~bits);
    System.out.println("setting bit: " + bits + " to: " + index);
}

Answer 1

你应该使用一个BitSet。如果你想自己做，你可以说:

public void set(int index) { 
    bits |= (1 << index);
}

如果这是家庭作业，并且上面的代码看起来很神奇，那么您确实需要阅读按位运算符。

这段代码可以解释为:

• 从数字 1 开始，将其所有位移动 index 次。
• 设置bits的值等于bits的值OR与上一步的值