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php - 如何使用 Laravel Eloquent 将多条记录插入数据库

转载 作者:塔克拉玛干 更新时间:2023-11-03 05:37:52 28 4
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我正在开发一个网络应用程序,出现了用户可以一次插入多条记录的场景。我在路由 result/create 创建了一个表单,用户可以在前端添加多行,现在当用户单击提交时,我希望将数组形式的所有记录/行数据插入数据库。现在,当我单击提交时,出现此错误 Undefined index: id

PS:我正在使用 Laravel 5.2 和资源 Controller 。

添加记录 View :

@extends('layouts.app')
@section('content')
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
<script type="text/javascript">
$(function () {
$('.add').click(function () {
var n = ($('.resultbody tr').length - 0) + 1;
var tr = '<tr><td class="no">' + n + '</td>' +
'<td><input type="text" class="name form-control" name="name[]" value="{{ old('name') }}"></td>'+
'<td><input type="text" class="fname form-control" name="fname[]" value="{{ old('fname') }}"></td>'+
'<td><input type="text" class="rollno form-control" name="rollno[]" value="{{ old('rollno') }}"></td>'+
'<td><input type="text" class="obtainedmarks form-control" name="obtainedmarks[]" value="{{ old('email') }}"></td>'+
'<td><input type="text" class="totalmarks form-control" name="totalmarks[]"></td>'+
'<td><input type="text" class="percentage form-control" name="percentage[]"></td>'+
'<td><input type="button" class="btn btn-danger delete" value="x"></td></tr>';
$('.resultbody').append(tr);
});
$('.resultbody').delegate('.delete', 'click', function () {
$(this).parent().parent().remove();
});
});
</script>
<div class="container">
<div class="row">
<div class="col-md-10 col-md-offset-1">
<div class="panel panel-default">
<div class="panel-heading">Add Results</div>

<div class="panel-body">
<form class="form-horizontal" role="form" method="POST" action="{{ url('/result') }}">
{!! csrf_field() !!}
<table class="table table-striped">
<thead>
<tr>
<th>ID</th>
<th>Student Name</th>
<th>Father Name</th>
<th>Roll No</th>
<th>Obtained Marks</th>
<th>Total Marks</th>
<th>%</th>
<th>Delete</th>
</tr>
</thead>
<tbody class="resultbody">
<tr>
<td class="no">1</td>
<td>
<input type="text" class="name form-control" name="name[]" value="{{ old('name') }}">
</td>
<td>
<input type="text" class="fname form-control" name="fname[]" value="{{ old('fname') }}">
</td>
<td>
<input type="text" class="rollno form-control" name="rollno[]" value="{{ old('rollno') }}">
</td>
<td>
<input type="text" class="obtainedmarks form-control" name="obtainedmarks[]" value="{{ old('email') }}">
</td>
<td>
<input type="text" class="totalmarks form-control" name="totalmarks[]">
</td>
<td>
<input type="text" class="percentage form-control" name="percentage[]">
</td>
<td>
<input type="button" class="btn btn-danger delete" value="x">
</td>
</tr>

</tbody>
</table>
<center><input type="button" class="btn btn-lg btn-primary add" value="Add New Item">
<input type="submit" class="btn btn-lg btn-default" value="Submit"></center>
</form>
</div>
</div>
</div>

</div><!-- First Row End -->
</div> <!-- Container End -->

@endsection

学生 Controller :

public function store(Request $request)
{
$input = Input::all();
$condition = $input['id'];
for($id = 0; $id<$condition; $id++){
$student = new Student;
$student->name = $input['name'][$id];
$student->save();
}
return view('students.index');
}

最佳答案

您收到该错误是因为您没有 id 表单域。试试这个:

public function store(Request $request)
{
$input = Input::all();
$condition = $input['name'];
foreach ($condition as $key => $condition) {
$student = new Student;
$student->name = $input['name'][$key];
$student->fname = $input['fname'][$key];
$student->rollno = $input['rollno'][$key];
$student->obtainedmarks = $input['obtainedmarks'][$key];
$student->totalmarks = $input['totalmarks'][$key];
$student->percentage = $input['percentage'][$key];
$student->save();
}
return view('students.index');
}

关于php - 如何使用 Laravel Eloquent 将多条记录插入数据库,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36799680/

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