javascript - 状态 200 上的 WebSocket 错误是什么？

Question

我已经购买了一个 WebSocket 模块并将其安装在我的 WAMP 环境中。我还有一个 PHP 脚本，它在正确的位置生成 IPC 文件并永远循环以监听事件。但是，使用此客户端代码:

var websocket = null;

var connect = function() {
    var button = document.getElementById('connect-button');
    // This function is a convenience function, to set the content
    // of the response display
    var setResponse = function(text) {
        var element = document.getElementById('response');
        element.innerHTML = text;
    }
    // A message telling the user we started connecting is always
    // useful
    button.innerHTML = 'Connecting ...';
    // The file name `demo.ws' could in principle help in having multiple
    // websockets at a single domain name.
    //
    // It's not implemented right now, but it can be if it's needed and
    // it's not too hard.    
    //var url = "ws://websocket-example/websocket-example/websocket-example-websocket.rp";
    var url = 'ws://' + window.location.hostname + '/WebSocket/websocket-example-websocket.rp';
    // Create the websocket connection now    
    websocket = new WebSocket(url, 'standard');
    // Install the handlers, the On Open handler is triggered
    // immediately after the conection has been established
    // and a successful handshake
    websocket.onopen = function(event) {
        // Update the connection status indicator
        var element = document.getElementById('connection-status');
        var input = document.getElementById('input');
        element.innerHTML = 'Connected Now';
        element.setAttribute('class', 'online');
        // Update the button, and install a new handler to allow
        // closing the websocket connection
        button.innerHTML = 'Close';
        button.onclick = function() {
            websocket.close();
        }
        input.focus();
        input.value = '';
    }
    // On close and on error handler, this is a simple demo
    // hence the simplistic approach. Ideally this should be
    // two separate functions
    websocket.onclose =
    websocket.onerror = function(event) {
        // Update the connection status indicator
        var element = document.getElementById('connection-status');
        var input = document.getElementById('input');
        element.innerHTML = 'Offline';
        element.setAttribute('class', 'offline');
        // Update button click handler, to reconnect if requested
        button.innerHTML = 'Connect';
        button.onclick = connect;
        input.value = '';
        // Clear the response text
        setResponse('');
        // Reset the websocket global variable
        websocket = null;
    }
    // On message handler, triggered when a message is received
    websocket.onmessage = function(event) {
        // Set the response text
        setResponse(event.data);
    }
}

var send = function(message) {
    // Send a message to the server but check that the websocket
    // was connected first
    if (websocket === null)
        return;
    // It's ok so, send the message now
    websocket.send(message);
}

当连接被触发时，我的请求失败并出现以下错误:

WebSocket connection to 'ws://websocket-example/WebSocket/websocket-example-websocket.rp' failed: Error during WebSocket handshake: Unexpected response code: 200

和websocket保持null。我完全不明白这个错误，因为 200 似乎是一个 OK 状态，但我的请求仍然失败。 IPC 文件是在服务器启动后生成的，位于正确的位置，执行脚本的用户具有请求该文件的必要权限。这种行为的原因是什么？我该如何解决？

Answer 1

在 WebSocket 连接上，您需要一个 101 Switching Protocols 状态响应。
获得 200 状态响应，可能意味着请求未到达您的 WebSocket 处理程序。

我还会查看开发工具，并检查响应是否有任何 WebSocket 握手 header 。
如果有，我会认为这是模块的问题。否则可能是您的配置问题。