php - super 鱼 : How to keep sub menu open after it has been clicked

Question

我遇到了以下情况。我有一个菜单，如果将鼠标悬停在菜单上，则会出现一个子菜单，如果鼠标移出，子菜单就会消失，现在我想要以下内容，如果我单击子菜单中的一个元素，我希望子菜单加载新页面时保持打开状态。为此，我正在使用 superfish Jquery 插件。

这可能吗？如果如何。

我的html代码

<div id="nav">
        <div id="nav2">
            <ul class="sf-menu sf-navbar ">
                <li>
                                        <a title="HOME" class="sf-with-ul " href="/index.php?r=site/index&amp;sid=1">HOME</a>               </li>   
            </ul>
            <ul class="sf-menu sf-navbar">
                <li>

                    <a href="?sid=2" id="gallery" class="sf-with-ul selected_main">GALLERY</a>
                    <ul class="subs" id="sub1"><li class="arrow"><img src="images/arrow.gif" /></li><li><a title="Kitchens" href="/index.php?r=images/sddsd&amp;id=1">Kitchens</a></li><li><a title="Vanities" href="/index.php?r=images/sddsd&amp;id=2">Vanities</a></li></ul>             </li>    
            </ul>
            <ul class="sf-menu sf-navbar ">
                <li>
                    <a href="?sid=3" class="sf-with-ul " >ACCESSORIES</a>
                                        <ul class="subs" id=""><li class="arrow"><img src="images/arrow.gif" /></li><li><a title="Door Handles" href="/index.php?r=images/sddsd&amp;id=2">Door Handles</a></li><li><a title="Spanners" href="/index.php?r=images/sddsd&amp;id=1">Spanners</a></li></ul>             </li>   
            </ul>

            <ul class="sf-menu sf-navbar ">
                <li>
                                        <a title="CONTACT US" class="sf-with-ul " href="/index.php?r=site/contact&amp;sid=4">CONTACT US</a>             </li>   
            </ul>   
        </div>

</div>

然后 super 鱼代码

$(function(){
             $("ul.sf-menu").superfish({ 
                 delay:         0,
                 speed:         'fast',
                 autoArrows:    false,
                 dropShadows:   false
            });
        });

我还注意到下面的 css 代码用于显示元素

left:   0;
top:    2.5em;
z-index:        99;

Answer 1

我发布 a demo为你。基本上我在 superfish 函数中添加了一个“onHide”函数，然后是一些额外的代码来保持菜单的持久性。

附加 CSS(默认 suckerfish.css)

.sf-menu li.sfSelected {
 background-color: #CFDEFF;
}

脚本

$(function(){
    var menu = $("#nav");

    menu.find("ul.sf-menu")
        .superfish({
            delay:         0,
            speed:         'fast',
            autoArrows:    false,
            dropShadows:   false,
            onHide:        function(){
                if (this.parent().is('.sfPersist')) {
                    this.show().css('visibility','visible').parent().addClass('sfHover');
                }
            }
        })
        .find('li > ul > li').click(function(){
            // hide previously persistent children (LOL that just sounds wrong)
            menu.find('.sfPersist')
                .removeClass('sfPersist sfHover')
                .find('> ul').hide().css('visibility','hidden');

            // add children that should be persistent
            if ($(this).is('.sfSelected')) {
                // if previously selected, keep hidden
                menu.find('li.sfSelected').removeClass('sfSelected');
            } else {
                // Hide other selected classes
                menu.find('li.sfSelected').removeClass('sfSelected');
                // if newly selected, then show
                $(this)
                    .addClass('sfSelected') // remember which one is selected
                    .parent()
                    .show().css('visibility','visible')
                    .parent().addClass('sfHover sfPersist');
            }
        });
});