java - 正则表达式测试失败 - Java

Question

我正在尝试执行简单的正则表达式。本质上，我想确定我的字符串中是否有特殊字符，如果有，则检查字符串的每个字符是否有两个特定字符，即连字符和点。

我似乎在第一位遇到了问题，涉及确定我的字符串中是否有特殊字符。

下面是我尝试执行此操作的方法，后面是我遇到问题的字符串:

public static boolean stringValidity(String input) {
    int specials = 0;

    Pattern p = Pattern.compile("[^a-zA-Z0-9 ]");
    Matcher m = p.matcher(input);
    boolean b = m.find();

    if (b) {
        System.out.println("\nstringValidity - There is a special character in my string");

        for (int i = 0; i < input.length(); ++i) {

           char ch = input.charAt(i);

           //if (!Character.isDigit(ch) && !Character.isLetter(ch) && !Character.isSpace(ch)) {
              ++specials;

              System.out.println("\nstringValidity - Latest number of special characters is: " + specials);

              if((ch == '-') | (ch == '.')) {
                  specialCharValidity = true;

                  System.out.println("\nstringValidity - CHAR is valid - specialCharValidity is: " + specialCharValidity + " as char is: " + ch);
              } else {
                  specialCharValidity = false;

                  System.out.println("\nstringValidity - CHAR is invalid - specialCharValidity is: " + specialCharValidity + " as char is: " + ch);

                  break;
              }
           //}
        }
    } else {
        System.out.println("\nstringValidity - There is NO special character in my string");

        specialCharValidity = true;
    }

    return specialCharValidity;
}

以下是我传递给方法的字符串，我希望将其视为具有特殊字符但测试失败的字符串:

"QWERTY"!£$"£$"
"sdfGSDFGSDFG%*^(%*&("

下面是我传递给方法的字符串，我希望这些字符串不会被视为具有特殊字符但测试失败的字符串:

"QWE12342134RTY"
"LOREMIPSUM2354214"

如有任何建议，我们将不胜感激。

Answer 1

您可以通过根据以下模式检查字符串来简化您的代码:

[^a-zA-Z0-9 \-\.]

字符串有效性函数归结为:

public static boolean stringValidity(String input) 
{
    return Pattern.compile("[^a-zA-Z0-9 \\-\\.]").matcher(input).find() == false;
}