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java - hibernate 条件 : Perform JOIN in Subquery/DetachedCriteria

转载 作者:塔克拉玛干 更新时间:2023-11-03 05:30:49 27 4
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我在使用 DetachedCriteria 将 JOIN 添加到子查询时遇到了问题。代码大致如下所示:

Criteria criteria = createCacheableCriteria(ProductLine.class, "productLine");
criteria.add(Expression.eq("productLine.active", "Y"));

DetachedCriteria subCriteria = DetachedCriteria.forClass(Model.class, "model");
subCriteria.setProjection(Projections.rowCount());
subCriteria.createAlias("model.modelLanguages", "modelLang");
subCriteria.createAlias("modelLang.language", "lang");
criteria.add(Expression.eq("lang.langCode", "EN"));
subCriteria.add(Restrictions.eqProperty("model.productLine.productLineId","productLine.productLineId"));
criteria.add(Subqueries.lt(0, subCriteria));

但记录的 SQL 不包含子查询中的 JOIN,但包含引发错误的别名

SELECT *
FROM PRODUCT_LINE this_
WHERE this_.ACTIVE=?
AND ? <
(SELECT COUNT(*) AS y0_
FROM MODEL this0__
WHERE lang3_.LANG_CODE ='EN'
AND this0__.PRODUCT_LINE_ID =this_.ID
)

如何将联接添加到 DetachedCriteria?


@Entity
@Table(name = "PRODUCT_LINE")
public class ProductLine implements java.io.Serializable {

private long productLineId;
private char active;
private Set<Models> models = new HashSet<Models>(0);

@OneToMany(fetch = FetchType.LAZY, mappedBy = "productLine")
public Set<Models> getModels() {
return this.models;
}

}

@Entity
@Table(name = "MODEL")
public class Model implements java.io.Serializable {

private long modelId;
private ProductLine productLine;
private String name;
private Set<ModelLanguages> modelLanguages = new HashSet<ModelLanguages>(0);

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "PRODUCT_LINE_ID")
public ProductLine getProductLine() {
return this.productLine;
}

@Column(name = "NAME", nullable = false)
public String getName() {
return this.name;
}

@OneToMany(fetch = FetchType.LAZY, mappedBy = "model")
public Set<ModelLanguages> getModelLanguages() {
return this.modelLanguages;
}

}

@Entity
@Table(name = "MODEL_LANGUAGES")
public class ModelLanguages implements java.io.Serializable {

private long id;
private Language language;
private Model model;

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "LANGUAGE_ID", nullable = false, insertable = false, updatable = false)
public Language getLanguage() {
return this.language;
}

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "MODEL_ID", nullable = false, insertable = false, updatable = false)
public Model getModel() {
return this.model;
}
}


@Entity
@Table(name = "LANGUAGES", uniqueConstraints = @UniqueConstraint(columnNames = "LANG_CODE"))
public class Language implements java.io.Serializable {

private long languageId;
private String langCode;
private Set<ModelLanguages> modelLanguages = new HashSet<ModelLanguages>(
0);

@Column(name = "LANG_CODE", unique = true, nullable = false)
public String getLangCode() {
return this.langCode;
}

@OneToMany(fetch = FetchType.LAZY, mappedBy = "language")
public Set<ModelLanguages> getModelLanguages() {
return this.modelLanguages;
}
}

Hibernate version: 3.2.6.ga
Hibernate core: 3.3.2.GA
Hibernate annotations: 3.4.0.GA
Hibernate commons-annotations: 3.3.0.ga
Hibernate entitymanager: 3.4.0.GA
Hibernate validator: 3.1.0.GA

最佳答案

您的代码中是否有以下行的拼写错误:

criteria.add(Expression.eq("lang.langCode", "EN"));

我认为,您应该在子标准而不是标准上添加此限制。

关于java - hibernate 条件 : Perform JOIN in Subquery/DetachedCriteria,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2602490/

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