algorithm - 冒泡排序算法 - Scilab

Question

我是计算机专业的一年级学生，无法让我的函数正常工作。我收到未公开的错误并且不知道为什么。

我已经让它工作了，但它没有在末尾显示列表或允许我使用 %T 和 %F 作为我的“转义” bool 变量。

有什么想法吗？

function x=sort(n,y);
disp("Enter numbers");
for i = 1:n
    x(i) = input('');
end

escape = 0;

if y == 1 then
    while escape == 0
        escape = 1;
        for i = 1:n
            if x(i+1) < x(i) then
                temp = x(i);
                x(i) = x(i+1);
                x(i+1) = temp;
                escape = 0;
            end
        end
    end
end

if y == 2 then
    while escape == 0
        escape = 1;
        for i == 1:n
            if x{i+1} > x{i} then
                temp = x{i};
                x{i} = x{i+1};
                x{i+1} = temp;
                escape = 0;
            end
        end
    end
end

disp(x(:));
endfunction;

a=input("Enter the number of values to sort: ");
b=input("Enter 1 for ascending, 2 for descending: ")
disp(sort(a,b));

Answer 1

这可能是因为您在各个地方的语法不正确(额外的分号，== 运算符而不是 for 语句中的 = 运算符，{} 括号，() 应该是括号，等等)。此外你的for周期必须来自 1至 n-1避免“无效索引”错误

function x=sort(n,y)
disp("Enter numbers")
for i = 1:n
    x(i) = input('')
end

escape = %f

if y == 1 then
    while escape == %f
        escape = %t
        for i = 1:n-1
            if x(i+1) < x(i) then
                temp = x(i)
                x(i) = x(i+1)
                x(i+1) = temp
                escape = %f
            end
        end
    end
end

if y == 2 then
    while escape == %f
        escape = %t
        for i = 1:n-1
            if x(i+1) > x(i) then
                temp = x(i)
                x(i) = x(i+1)
                x(i+1) = temp
                escape = %f
            end
        end
    end
end

endfunction

a=input("Enter the number of values to sort: ")
b=input("Enter 1 for ascending, 2 for descending: ")
disp(sort(a,b))