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c++ - 如何在 C++ 中正确使用优先级队列

转载 作者:塔克拉玛干 更新时间:2023-11-03 05:22:45 25 4
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对于我的数据结构类中的作业,我假设要针对所谓的背包问题实现分支定界法。问题本身不是问题,但如果你不知道它是问题涉及找到包含最大利润的项目集,前提是项目的总重量不超过变量 W。有关该问题的更多信息,请参阅评论在代码中。我的问题是,当尝试使用 push 函数将节点插入优先级队列时,它会给我一些看起来像这样的错误消息

no matching function for call to ‘std::priority_queue<int>::push(node&)’

我过去使用过队列,但没有使用过优先级队列,而且我已经对如何在 C++ 中使用它们进行了大量研究。但是,似乎没有什么对我有用。如果有人能指出我在使用优先级队列方面做错了什么,我将不胜感激。这是我的代码,请注意所有函数都在一个名为 knapsack3.cpp 的文件中:

主要功能

 /*Let n items be given, where each item has a weight and a profit. The weights
and profits as positive integers. Furthermore, let a positive interger W be given.
Determine a set of items with the maximum total profit, under the condition that
the sum of their weights cannot exceed W. */

//Preprocessor Directives
#include <stdio.h>
#include <queue>
#include <iostream>

//node data structure
struct node { int level; int profit; int weight; float bound; };
using namespace std;

//function protocol
void knapsack3(int n, int p[], int w[], int W, int* maxprofit);
float bound(int n, int p[], int w[], int W, node u);

//declare arrays
int p[5]; //holds profit values for 5 items
int w[5]; //hold weight values for 5 items

int main() {
//declare variables
int n = 5; int i; int W = 13; int maxprofit = 0;
//enter values for profit and weight in a way that each of which is sorted in
//decreasing order according to the values of p[i]/w[i]
printf("Enter Profits\n");
for(i=0; i<n; i++)
scanf("%d", &p[i]);
printf("Enter Weights\n");
for(i=0; i<n; i++)
scanf("%d", &w[i]);

std::queue<int> PQ;
knapsack3(n, p, w, W, &maxprofit);
//print value for maxprofit
printf("%d\n", maxprofit); }

背包功能

//function that finds the maxprofit that is the sum of the profits of an optimal set.
void knapsack3(int n, int p[], int w[], int W, int* maxprofit)
{
//initialize priority queue PQ
priority_queue<int>PQ;
//initialize nodes u and v
node u, v;

//initialize PQ to be empty
v.level = 0; v.profit = 0; v.weight = 0;
maxprofit = 0;
//initialize v to be the root
v.bound = bound(n, p, w, W, v);
PQ.push(v);

//remove node with best bound
while(!empty(PQ)){
PQ.pop();

//check if node is still promising
if(v.bound > maxprofit){
u.level = v.level + 1;
//set node u to the child node that includes the next item
u.weight = v.weight + w[u.level];
u.profit = v.profit + p[u.level];

if(u.weight <= W && u.profit > maxprofit)
maxprofit = u.profit;
u.bound = bound(n, p, w, W, u);
if(u.bound > maxprofit)
PQ.push(u);
//set node u to the child node that does not include the next item
u.weight = v.weight;
u.profit = v.profit;
u.bound = bound(n, p, w, W, u);
if(u.bound > maxprofit)
PQ.push(u);
}
}
}

绑定(bind)函数

//function that returns the bound of a node
float bound(int n, int p[], int w[], int W, node u)
{
int j, k;
int totalweight;
float result;
if(u.weight >=W)
return 0;
else{
result = u.profit;
j = u.level + 1;
totalweight + u.weight;
while(j<=n && totalweight + w[j] <= W){
totalweight = totalweight + w[j];
result = result p[j];
j++;
}
k=j;
if(k<=n)
result = result + (W-totalweight) * p[k]/w[k];
return result;
}
}

最佳答案

您正在尝试推送 struct node进入为 int 输入的队列.尝试将您的 PQ 类型更改为 priority_queue<node>

关于c++ - 如何在 C++ 中正确使用优先级队列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26942475/

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