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Java多播发送数据,不接收

转载 作者:塔克拉玛干 更新时间:2023-11-03 05:14:51 26 4
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我正在用 Java 编写一个类,用于大大简化多播过程。但是,我有两个大问题:

  1. 类(class)发送数据(我可以用我的网络监视器 Wireshark 验证这一点)但同一组中的任何其他人都没有收到数据。
  2. 在某些机器上,发送数据包的 TTL 在传输过程中被超过(同样,根据 Wireshark)。

谁能帮帮我?几个小时以来,我一直在尝试并寻找答案,看来我的代码遵循了连接、加入、发送和接收来自多播主机的数据的所有基本过程。

这是该类(class)相关部分的片段:

多路广播类:

public class Multicaster {
public int port = 5540;

protected String IPAddress;

private MulticastSocket msConn;
private InetAddress netAddr;

public Multicaster(String IPAddress) {
this.IPAddress = IPAddress;
}

public String recieveData() {
byte[] buf = new byte[1000];
DatagramPacket pack = new DatagramPacket(buf, buf.length);

try {
this.msConn.receive(pack);
new Message(pack);
String out = new String(pack.getData());
return out.substring(0, pack.getLength());
} catch (IOException e) {
return new String("");
}
}

public void joinGroup() {
try {
this.msConn.joinGroup(this.netAddr);
} catch (IOException e) {
//This error shouldn't occur since it would caught by the connect() method during initial connection to the host
}
}

public void connect() throws MulticasterInitException {
//Try to create a multicast connection on the given IP address and port
try {
try {
//Create a multicast connection on a given port, throws UnknownHostException
this.msConn = new MulticastSocket(this.port);

//If all goes well, then create a connection to a given IP address using the above port number, throws IOException and SecurityException
this.netAddr = InetAddress.getByName(this.IPAddress);
}
}

/**
* Here all of the possible exceptions that are thrown above
* are caught and handled here. This works just fine.
*/
}

public void sendData(String data) throws MulticasterSendException {
DatagramPacket packet = new DatagramPacket(data.getBytes(), data.length(), this.netAddr, this.port);

try {
this.msConn.send(packet);
} catch (IOException e) {
throw new MulticasterSendException("Java could not communicate with the server. Please check your network connections.", e);
}
}
}

发送数据的示例用法:

Multicaster multicast = new Multicaster("239.0.0.0");

try {
multicast.connect();
} catch (MulticasterInitException e) {
//Handle exception...
}

multicast.joinGroup();

try {
multicast.sendData("Hi");
} catch (MulticasterSendException e) {
//Handle exception...
}

接收数据的示例用法:

Multicaster multicast = new Multicaster("239.0.0.0");

try {
multicast.connect();
} catch (MulticasterInitException e) {
//Handle exception...
}

multicast.joinGroup();
System.out.print(multicast.recieveData());

最佳答案

我以前遇到过类似的问题,必须确保在接收端指定了 NetworkInterface。

SocketAddress socketAddress = new InetSocketAddress(groupIp, groupPort);
NetworkInterface networkInterface = NetworkInterface.getByName(interfaceName);

socket.joinGroup(socketAddress, networkInterface);

interfaceName 是在 Linux 或 Mac 上运行 ifconfig 时显示的接口(interface)名称之一。

关于Java多播发送数据,不接收,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8471403/

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