java - 如何通过按 DELETE 键从 jTable 中删除一个单元格？

Question

我有如下代码。我想通过按删除键删除单元格。我怎样才能做到这一点？我还想在该字段中添加删除按钮。

private static final long serialVersionUID = -250883760398754970L;
private final LinkedList<Product> list= new LinkedList<Product>();
    private final LinkedList<Boolean> checkList = new LinkedList<Boolean>();
    public void addItem(Product customer) {
    list.add(customer);
    checkList.add(false);
    fireTableDataChanged();

}
@Override
public int getColumnCount() {
        return 6;
}

@Override
public int getRowCount() {
    return list.size();

}

@Override
public Object getValueAt(int rowIndex, int columnIndex) {
    Object obj = null;

    if(columnIndex==4)
       {
    setTotal(list.get(rowIndex));
    }
             switch (columnIndex){
        case 0: obj= list.get(rowIndex).getCode() ;break;
        case 1: obj=list.get(rowIndex).getDescription(); break;
        case 2: obj=list.get(rowIndex).getQuantity();break;
        case 3: obj=list.get(rowIndex).getPrice();break;            
        case 4: obj=list.get(rowIndex).getTotal();break;
    }
    return obj;
}
    @Override
public Class<?> getColumnClass(int arg0) {

    switch(arg0){
    case 0: case 1: return String.class; 
    case 2: return Integer.class; 
    case 3: case 4: return Double.class;
    }

    return super.getColumnClass(arg0);
}
@Override
public boolean isCellEditable(int arg0, int arg1) {
    boolean isCellEditable = false;
    switch(arg1){
    case 2: case 3: isCellEditable= true;break;
    default: isCellEditable= false;break;
    }
    return isCellEditable;
    //return super.isCellEditable(arg0, arg1);
}


@Override

public void setValueAt(Object arg0, int arg1, int arg2) {
    System.out.println("Value seted" +arg0 + arg1 + arg2);


    switch(arg2){
    case 0: break;
    case 1: break;
    case 2: list.get(arg1).setQuantity((Integer)arg0);             setTotal(list.get(arg1)); break;
    case 3: list.get(arg1).setPrice((Double)arg0); setTotal(list.get(arg1));break;          
    case 4: list.get(arg1).setTotal((Double)arg0);break;



       //case 0: checkList.set(arg1, (Boolean)arg0);break;
       default:break;
    }
    //list.get(arg1).setTotal((Double)arg0);
    fireTableDataChanged();
}



public LinkedList<Product> getList() {
    LinkedList<Product> temp = new LinkedList<Product>();
    int index=-1;
    for(Boolean isSelected:checkList){
        index++;
        if(isSelected){
            temp.add(list.get(index));
        }
    }
    return temp;
}


public void setTotal(Product product){
    Double total = 0.0d;
    total = product.getQuantity ()* product.getPrice();
    product.setTotal(total);

}

这个代码可以吗？谢谢。

Answer 1

您需要将删除键绑定(bind)到表。

看看How to use Key Bindings了解更多详情

InputMap inputMap = table.getInputMap(WHEN_FOCUSED);
ActionMap actionMap = table.getActionMap();

inputMap.put(KeyStroke.getKeyStroke(KeyEvent.VK_DELETE, 0), "delete");
actionMap.put("delete", new AbstractAction() {
    public void actionPerformed(ActionEvent evt) {
       // Note, you can use getSelectedRows() and/or getSelectedColumns
       // to get all the rows/columns that have being selected
       // and simply loop through them using the same method as
       // described below.
       // As is, it will only get the lead selection
       int row = table.getSelectedRow();
       int col = table.getSelectedColumn();
       if (row >= 0 && col >= 0) {
           row = table.convertRowIndexToModel(row);
           col = table.convertColumnIndexToModel(col);
           table.getModel().setValueAt(null, row, col);
       }
    }
});

这只是一个例子。您可以使用相同的想法删除整行，只要您的表格模型支持它即可。