java - 在 Java 中将字符串解析为日期时出错

Question

是的，另一个 Java Date 帖子 :)

我的问题:

简单的标准代码，用于测试插入的日期是否符合要求的格式 (dd/MM/yyyy):

SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
try {

   sdf.parse(strDate); 

} catch(ParseException e) {

   // err

}

strDate = "10-12-2012" ----> sysout = err (ok)

strDate = "2012-11-10" ----> sysout = err (ok)

strDate = "15/10/2011" ----> sysout = parse (ok)

问题:

strDate = "2012/12/15" ----> sysout = this date that i expect an error result parsed like "Tue Jun 03 00:00:00 CET 21"

谁知道？？？

Answer 1

只需设置setLenient为假。

来自 API:

setLenient method:

Specify whether or not date/time parsing is to be lenient. With lenient parsing, the parser may use heuristics to interpret inputs that do not precisely match this object's format. With strict parsing, inputs must match this object's format.

SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
try {
  sdf.setLenient(false);
  System.out.println(sdf.parse("2012/12/15")); 
} catch(ParseException e) {
  e.printStackTrace();
}