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java - com.thoughtworks.xstream.mapper.CannotResolveClassException

转载 作者:塔克拉玛干 更新时间:2023-11-03 05:02:02 39 4
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这是我第一次尝试 XStream。但是当我尝试解析我的 xml 文件时,出现了这个异常:

Exception in thread "main" com.thoughtworks.xstream.mapper.CannotResolveClassException: root
at com.thoughtworks.xstream.mapper.DefaultMapper.realClass(DefaultMapper.java:79)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.DynamicProxyMapper.realClass(DynamicProxyMapper.java:55)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.PackageAliasingMapper.realClass(PackageAliasingMapper.java:88)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.ClassAliasingMapper.realClass(ClassAliasingMapper.java:79)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.ArrayMapper.realClass(ArrayMapper.java:74)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.CachingMapper.realClass(CachingMapper.java:45)
at com.thoughtworks.xstream.core.util.HierarchicalStreams.readClassType(HierarchicalStreams.java:29)
at com.thoughtworks.xstream.core.TreeUnmarshaller.start(TreeUnmarshaller.java:133)
at com.thoughtworks.xstream.core.AbstractTreeMarshallingStrategy.unmarshal(AbstractTreeMarshallingStrategy.java:32)
at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1157)
at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1141)
at com.thoughtworks.xstream.XStream.fromXML(XStream.java:1012)
at com.mmm.transport.se.xmleditor.xml.TestXML.test(TestXML.java:20)
at com.mmm.transport.se.xmleditor.domain.Main.main(Main.java:13)

所以我们可以看到错误出现在我的 testXML 类中的第 20 行。它看起来像这样:

public class TestXML {

public void test() throws FileNotFoundException {

FileReader reader = new FileReader("xmlFiles/CoreDatamodel.xml");

XStream xstream = new XStream();
xstream.processAnnotations(Properties.class);
xstream.processAnnotations(Parameters.class);
xstream.processAnnotations(ObjType.class);
xstream.processAnnotations(Type.class);
Type data = (Type) xstream.fromXML(reader);

System.out.println(data);
}

}

第 20 行是这一行:xstream.processAnnotations(Parameters.class);

@XStreamAlias("param")
public class Parameters {

@XStreamAlias("DATATYPE")
private String datatype;
@XStreamAlias("DESCRIPTION")
private String description;
@XStreamAlias("MIN_NO")
private String min_no;
@XStreamAlias("MAX_NO")
private String max_no;
@XStreamAlias("ORDER1")
private String order1;
@XStreamAlias("NESTED")
private String nested;
@XStreamAlias("DEFAULT1")
private String default1;
@XStreamAlias("FORMAT")
private String format;
@XStreamAlias("PARAMETER")
private String parameter;

public Parameters(String datatype, String description, String min_no,
String max_no, String order1, String nested, String default1,
String format, String parameter) {
super();

setDatatype(datatype);
setDescription(description);
setMin_no(min_no);
setMax_no(max_no);
setOrder1(order1);
setNested(nested);
setDefault1(default1);
setFormat(format);
setParameter(parameter);

} //Getters and setters..

xml 看起来像这样:

- <root>
- <info>
<CORE_NAME>DataModel_Core</CORE_NAME>
<CORE_VERSION>..</CORE_VERSION>
<CORE_PRODUCT_ID>...</CORE_PRODUCT_ID>
<ADAPTATION_NAME />
<ADAPTATION_VERSION />
<ADAPTATION_PRODUCT_ID />
</info>
- <type>
<OBJECT_TYPE>data</OBJECT_TYPE>
- <prop>
<DESCRIPTION>Site parameters</DESCRIPTION>
<PARENT>NULL</PARENT>
<VIRTUAL>0</VIRTUAL>
<VISIBLE>1</VISIBLE>
<PICTURE>NULL</PICTURE>
<HELP>10008</HELP>
<MIN_NO>1</MIN_NO>
<MAX_NO>1</MAX_NO>
<NAME_FORMAT>NULL</NAME_FORMAT>
</prop>
- <param>
<PARAMETER>nidRbc</PARAMETER>
<DATA_TYPE>INTEGER</DATA_TYPE>
<DESCRIPTION>RBC identity</DESCRIPTION>
<MIN_NO>1</MIN_NO>
<MAX_NO>1</MAX_NO>
<ORDER1>1</ORDER1>
<NESTED>0</NESTED>
<DEFAULT1>NULL</DEFAULT1>
<FORMAT>0:16382</FORMAT>
</param>
</type>

涉及的其他类如下所示:

public class Type {

@XStreamImplicit(itemFieldName = "type")
private List types = new ArrayList();

}

public class ObjType {

@XStreamAlias("OBJECT_TYPE")
private String objectType;

public ObjType() {

} // Getters and setters

@XStreamAlias("prop")
public class Properties {

@XStreamAlias("DESCRIPTION")
private String description;
@XStreamAlias("PARENT")
private String parent;
@XStreamAlias("VIRTUAL")
private String virtual;
@XStreamAlias("VISIBLE")
private String visible;
@XStreamAlias("PICTURE")
private String picture;
@XStreamAlias("HELP")
private String help;
@XStreamAlias("MIN_NO")
private String min_no;
@XStreamAlias("MAX_NO")
private String max_no;
@XStreamAlias("NAME_FORMAT")
private String name_format;
public static Properties instance = null;

public static Properties getInstance() {

if (instance == null) {

instance = new Properties();

}

return instance;
}

public Properties() {

} // Getters and Setters.

这个错误的原因是什么?

最佳答案

你得到这个异常的原因是因为你没有你的 xml 的 xml 元素根和信息的表示。

因此,当 XStream 读取该 xml 文件时,它正在搜索与根元素匹配的类。如果您没有定义别名/映射,它将尝试将标记名称作为类名称。

所以,而不是:

public class Type {
@XStreamImplicit(itemFieldName = "type")
private List types = new ArrayList();
}

使用类似的东西:

@XStreamAlias("root")
public class Type {
private Info info;

@XStreamImplicit(itemFieldName = "type")
private List types = new ArrayList();
}

private class Info {
// ... define the attributes for the info element here.
}

为了您的引用,我已经格式化了您的 xml 以提高可读性:

<root>
<info>
<CORE_NAME>DataModel_Core</CORE_NAME>
<CORE_VERSION>..</CORE_VERSION>
<CORE_PRODUCT_ID>...</CORE_PRODUCT_ID>
<ADAPTATION_NAME />
<ADAPTATION_VERSION />
<ADAPTATION_PRODUCT_ID />
</info>
<type>
<OBJECT_TYPE>data</OBJECT_TYPE>
<prop>
<DESCRIPTION>Site parameters</DESCRIPTION>
<PARENT>NULL</PARENT>
<VIRTUAL>0</VIRTUAL>
<VISIBLE>1</VISIBLE>
<PICTURE>NULL</PICTURE>
<HELP>10008</HELP>
<MIN_NO>1</MIN_NO>
<MAX_NO>1</MAX_NO>
<NAME_FORMAT>NULL</NAME_FORMAT>
</prop>
<param>
<PARAMETER>nidRbc</PARAMETER>
<DATA_TYPE>INTEGER</DATA_TYPE>
<DESCRIPTION>RBC identity</DESCRIPTION>
<MIN_NO>1</MIN_NO>
<MAX_NO>1</MAX_NO>
<ORDER1>1</ORDER1>
<NESTED>0</NESTED>
<DEFAULT1>NULL</DEFAULT1>
<FORMAT>0:16382</FORMAT>
</param>
</type>
</root>

关于java - com.thoughtworks.xstream.mapper.CannotResolveClassException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21283052/

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