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javascript - 二叉表达式树的中缀

转载 作者:塔克拉玛干 更新时间:2023-11-03 05:00:02 24 4
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我有像这样的中缀表达式:

((source = id)AND (target= id) AND ( NOT( color != blue) OR ( age<= 23 )))

如何转换为如下 TreeMap 所示的二叉树。我刚开始用 javascript 编写代码,但不知道如何编写插入操作,尤其是像 NOT 这样的一元运算符。如何解决这个问题。

enter image description here

var Node = function(data,left,right){
this.data = data;
this.left = left;
this.right = right;
};


var BinaryTree = function(){
this.head = new Node(null,null,null);
};

BinaryTree.prototype.insert = function(data){
if(this.head.data == null){
this.head = new Node(data,null,null);
} else{
var current = this.head;
insert(current,data);
}
};

var insert = function(current,data){
// How to insert ?
};

最佳答案

正如昨晚所说,这里是我必须要说的重点:

图节点:

//abstract base-class
class GraphNode {
constructor(){
Object.defineProperty(this, "parent", {
writable: true,
//enumerable: false, //so it doesn't show up in JSON
value: null
})
}
compute(ctx){ throw new Error("not implemented") }
toString(){ throw new Error("not implemented") }
}

//leaf-nodes
class ValueNode extends GraphNode{
constructor(value){
super();
this.value = value;
}
compute(){ return this.value; }
toString(){ return JSON.stringify(this.value); }
}

class PropertyNode extends GraphNode{
constructor(property){
super();
this.property = property;
}
compute(ctx){ return ctx[this.property]; }
toString(){ return String(this.property); }
}

//tree-nodes
class UnaryNode extends GraphNode{
constructor(op, node){
if(!(node instanceof GraphNode)){
throw new Error("invalid node passed")
}
super();
this.op = op;
this.node = node;
node.parent = this;
}
compute(ctx){
var v = this.node.compute(ctx);
switch(this.op){
case "NOT": return !v;
}
throw new Error("operator not implemented '"+this.op+"'");
}
toString(){
return "( " + this.op + " " + this.node.toString() + " )";
}
}
UnaryNode.operators = ["NOT"];


class BinaryNode extends GraphNode{
constructor(op, l, r){
if(!(l instanceof GraphNode && r instanceof GraphNode)){
throw new Error("invalid node passed")
}
super();
this.op = op;
this.left = l;
this.right = r;
l.parent = this;
r.parent = this;
}
compute(ctx){
var l = this.left.compute(ctx);
var r = this.right.compute(ctx);
switch(this.op){
//logic operators
case "AND": return l && r;
case "OR": return l || r;

//comparison-operators
case "=": return l === r;
case "<=": return l <= r;
case ">=": return l >= r;
case "!=": return l != r;
case ">": return l > r;
case "<": return l < r;

//computational operators
case "+": return l + r;
case "-": return l - r;
case "*": return l * r;
case "/": return l / r;
}
throw new Error("operator not implemented '"+this.op+"'");
}

toString(){
return "( " + this.left.toString() + " " + this.op + " " + this.right.toString() + " )";
}
}
//also defines precendence
BinaryNode.operators = [
"*","/","+","-",
">","<","<=",">=","!=","=",
"AND","OR",
]

//dot is kind of special:
class DotNode extends BinaryNode{
constructor(l, r){
/*
if(!(l instanceof PropertyNode || l instanceof DotNode)){
throw new Error("invalid left node")
}
*/
if(!(r instanceof PropertyNode)){
throw new Error("invalid right node")
}
super(".", l, r);
}

compute(ctx){
//especially because of this composition:
//fetch the right property in the context of the left result
return this.right.compute( this.left.compute(ctx) );
}
toString(){
return this.left.toString() + "." + this.right.toString();
}
}

解析器:

function escapeForRegex(str){
return String(str).replace(/[.*+?^=!:${}()|[\]\/\\]/g, '\\$&');
}

//dynamically build my parsing regex:
var tokenParser = new RegExp([
//numbers
/\d+(?:\.\d*)?|\.\d+/.source,

//string-literal
// /["](?:\\[\s\S]|[^"])+["]|['](?:\\[\s\S]|[^'])+[']/.source,

//booleans
//"true|false",

//operators
[".", "(", ")"].concat(UnaryNode.operators, BinaryNode.operators)
.sort((a,b) => b.length-a.length) //so that ">=" is added before "=" and ">", for example
.map(escapeForRegex)
.join("|"),

//properties
//has to be after the operators
/[a-zA-Z$_][a-zA-Z0-9$_]*/.source,

//remaining (non-whitespace-)chars, just in case
//has to be at the end
/\S/.source
].map(s => "("+ s +")").join("|"), "g");

function parse(str){
var tokens = [];
//abusing str.replace() as a RegExp.forEach
str.replace(tokenParser, function(token, number, op, property){
if(number){
token = new ValueNode(+number);
//}else if(string){
// token = new ValueNode(JSON.parse(string));
//}else if(bool){
// token = new ValueNode(bool === "true");
}else if(property){
token = new PropertyNode(property);
}else if(!op){
throw new Error("unexpected token '"+token+"'");
}
tokens.push(token);
});

for(var i; (i=tokens.indexOf(".")) > -1; ){
tokens.splice(i-1, 3, new DotNode(tokens[i-1], tokens[i+1]))
}

for(var i,j; (i=tokens.lastIndexOf("(")) > -1 && (j=tokens.indexOf(")", i)) > -1;){
tokens.splice(i, j+1-i, process(tokens.slice(i+1, j)));
}
if(~tokens.indexOf("(") || ~tokens.indexOf(")")){
throw new Error("mismatching brackets");
}

return process(tokens);
}

function process(tokens){
UnaryNode.operators.forEach(token => {
for(var i=-i; (i=tokens.indexOf(token, i+1)) > -1;){
tokens.splice(i, 2, new UnaryNode(token, tokens[i+1]));
}
})

BinaryNode.operators.forEach(token => {
for(var i=1; (i=tokens.indexOf(token, i-1)) > -1;){
tokens.splice(i-1, 3, new BinaryNode(token, tokens[i-1], tokens[i+1]));
}
});

if(tokens.length !== 1){
console.log("error: ", tokens.slice());
throw new Error("something went wrong");
}
return tokens[0];
}

及其用法:

var tree = parse("((a.source = id)AND (target= id) AND ( NOT( color != blue) OR ( age<= 23 )))")
//var tree = parse("1=1=age+10>30"); //to test operator precedence

var data = {
id: 12345,

a: { source: 12345 },
target: 12345,

color: "#FF0",
blue: "#00F",

age: 20
}

console.log(tree.compute(data));
console.log(tree.toString());
console.log(JSON.stringify(tree, null, 2));

关于javascript - 二叉表达式树的中缀,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37469768/

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