java - 如何禁用/避免 Java-XML 中的 Ampersand-Escaping？

Question

我想创建一个 XML，其中空格被替换为  。但是 Java-Transformer 转义了 A 符号，所以输出是  

这是我的示例代码:

public class Test {

    public static void main(String[] args) {

        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = factory.newDocumentBuilder();
        Document document = builder.newDocument();

        Element element = document.createElement("element");
        element.setTextContent(" ");
        document.appendChild(element);

        ByteArrayOutputStream stream = new ByteArrayOutputStream();
        Transformer transformer = TransformerFactory.newInstance().newTransformer();
        StreamResult streamResult = new StreamResult(stream);
        transformer.transform(new DOMSource(document), streamResult);
        System.out.println(stream.toString());

    }

}

这是我的示例代码的输出:

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<element>&amp;#160;</element>

有什么解决或避免这种情况的想法吗？非常感谢!

Answer 1

使用输出转义如下:

Node disableEscaping = document.createProcessingInstruction(StreamResult.PI_DISABLE_OUTPUT_ESCAPING, "&");
 Element element = document.createElement("element");
 element.setTextContent(" ");
 document.appendChild(disableEscaping );
 document.appendChild(element);
Node enableEscaping = document.createProcessingInstruction(StreamResult.PI_ENABLE_OUTPUT_ESCAPING, "&");
document.appendChild(enableEscaping )