javascript - 超过最大调用堆栈 RangeError

Question

smallestInteger = (stack,numbers,k) => {
    if (stack.length == 0){
        stack.push(numbers[k]);
    }
    if (numbers[k] <= stack[stack.length-1]){
        stack.pop();
        stack.push(numbers[k]);
    } 
    console.log(`stack is ${stack}`)
    console.log("k:" + k);
    return (k == 0) ? stack[stack.length-1] : smallestInteger(stack,numbers,k-1);
}

var smallestInteger = function(numbers) {
    let stack = []; 
    let smallest = smallestInteger(stack ,numbers,numbers.length - 1);
    return `the smallest integer is ${smallest}`;
}

var testCases = [[10,2,5,7,15,9], [1,2,3,4]];
for (let testCase of testCases){
    console.log(smallestInteger(testCase));
}

运行 > node smallestInteger.js 给出了这个错误:

RangeError: Maximum call stack size exceeded
    at smallestInteger (smallestInteger.js:17:31)
    at smallestInteger (smallestInteger.js:19:17)
    at smallestInteger (smallestInteger.js:19:17)
    at smallestInteger (smallestInteger.js:19:17)
    at smallestInteger (smallestInteger.js:19:17)
    at smallestInteger (smallestInteger.js:19:17)
    at smallestInteger (smallestInteger.js:19:17)
    at smallestInteger (smallestInteger.js:19:17)
    at smallestInteger (smallestInteger.js:19:17)
    at smallestInteger (smallestInteger.js:19:17)

仅供引用，代码未到达 console.log 打印语句，我该如何解决？

这两个 smallestInteger 函数有不同的构造函数(第一个有 1 个参数，另一个有 3 个)就像覆盖一样，所以我不认为它们会相互替换。你在哪里看到它得到 2 个参数，它按预期得到 3 个参数。最后，smallestInteger 函数正在调用 smallestInteger 辅助函数，它在 ? 之后有一个退出条件，即 k == 0 所以它不应该永远持续下去。仍然出现同样的错误

Answer 1

Javascript 不允许重载函数。为此，您需要发挥创造力。例如:

function smallestInteger(stack,numbers,k){
if (arguments.length == 1) {
    numbers = stack;
    stack = []; 
    let smallest = smallestInteger(stack ,numbers,numbers.length - 1);
    return `the smallest integer is ${smallest}`;
  }

if (stack.length == 0){
    stack.push(numbers[k]);
}
if (numbers[k] <= stack[stack.length-1]){
    stack.pop();
    stack.push(numbers[k]);
} 
return (k == 0) ? stack[stack.length-1] : smallestInteger(stack,numbers,k-1);
}

var testCases = [[10,2,5,7,15,9], [1,2,3,4]];
for (let testCase of testCases){
    console.log('testCase : ', testCase);
    console.log(smallestInteger(testCase));
}