java - 按字母顺序排列的元音单词

Question

该程序的目标是从包含所有 6 个元音(包括 y)的单词列表中返回单词。元音按字母顺序排列的地方。例如，答案可能类似于:Aerious(尽管 Aerious 不起作用，因为它没有 y)。目前该程序不返回任何单词。我认为 containsVowels 方法不正确。

public static void question11() {
    System.out.println("Question 11:");
    System.out.println("All words that have 6 vowels once in alphabetical order: ");
    String vowelWord = "";

    for (int i = 1; i< WordList.numWords(); i++) {
        if (containsVowels(WordList.word(i))) {       
            if (alphabetical(WordList.word(i))) {
                vowelWord = WordList.word(i);
                System.out.println(vowelWord);
            }
        }
    }

    return;
}

public static boolean alphabetical(String word) {
    int vowelPlaceA = 0;
    int vowelPlaceE = 0;
    int vowelPlaceI = 0;
    int vowelPlaceO = 0;
    int vowelPlaceU = 0;
    int vowelPlaceY = 0;

    for (int i = 0; i < word.length(); i++) {
        if (word.charAt(i) == 'a') {
            vowelPlaceA = i;
        }
        if (word.charAt(i) == 'e') {
             vowelPlaceE = i;
        }
        if (word.charAt(i) == 'i') {
             vowelPlaceI = i;
        }
        if (word.charAt(i) == 'o') {
             vowelPlaceO = i;
        }
        if (word.charAt(i) == 'u') {
             vowelPlaceU = i;
        }
        if (word.charAt(i) == 'y') {
             vowelPlaceY = i;
        }
        //check a alphabetical
        if(vowelPlaceA > vowelPlaceE || vowelPlaceA > vowelPlaceI || vowelPlaceA > vowelPlaceO ||
          vowelPlaceA > vowelPlaceU || vowelPlaceA > vowelPlaceY) {
             return false;
        }
        //check e alphabetical
        if(vowelPlaceE > vowelPlaceI || vowelPlaceE > vowelPlaceO ||
          vowelPlaceE > vowelPlaceU || vowelPlaceE > vowelPlaceY) {
             return false;
        }
        //i
        if(vowelPlaceI > vowelPlaceO || vowelPlaceI > vowelPlaceU || vowelPlaceI > vowelPlaceY) {
             return false;
        }
        //o
        if(vowelPlaceO > vowelPlaceU || vowelPlaceO > vowelPlaceY) {
             return false;
        }
        //u
        if(vowelPlaceU > vowelPlaceY) {
             return false;
        }    
    }
    return true;
}

public static boolean containsVowels(String word) {
    String vowels = "aeiouy";
    if (word.contains(vowels)) {
        return true;
    }
    return false;
}

Answer 1

您可以在方法中简单地使用正则表达式:

public static boolean containsVowels(String word) {
    return Pattern.matches(".*a.*e.*i.*o.*u.*y.*", word);
}