Java 字符串拆分为非字母字符

Question

我想将一个字符串沿非字母字符拆分为一个字符串数组。例如:

"Here is an ex@mple" => "Here", "is", "an" "ex", "mple"

我尝试使用 String.split(String regex)使用正则表达式 "(?![\\p{Alpha}])" 的方法。然而，这会将字符串拆分为

"Here", "_is", "_an", "_ex", "@ample"

(那些下划线是为了强调有一个空格)。我猜这是因为 ?! 正则表达式运算符是“零宽度”的，实际上是拆分和删除输入字符串中非字母字符之前的零宽度字符。

如何在拆分字符串时删除实际的非字母字符？是否存在非零宽度否定运算符？

Answer 1

你可以尝试 \P{Alpha}+:

"Here is an ex@mple".split("\\P{Alpha}+")

["Here", "is", "an", "ex", "mple"]

\P{Alpha} matches any non-alphabetic character (as opposed to \p{Alpha}, which matches any alphabetic character). + indicates that we should split on any continuous string of such characters. For example:

"a!@#$%^&*b".split("\\P{Alpha}+")

["a", "b"]