java - 如何检查一个 ArrayList of Strings 是否包含另一个 ArrayList of Strings 的子字符串？

Question

List<String> actualList = Arrays.asList ("mother has chocolate", "father has dog");
List<String> expectedList = Arrays.asList ("mother", "father", "son", "daughter");

有没有办法检查 expectedList 是否包含 actualList 中字符串的任何子字符串？

我找到了一个嵌套的 for-each 解决方案:

public static boolean hasAny(List<String> actualList, List<String> expectedList) {
    for (String expected: expectedList)
        for (String actual: actualList)
            if (actual.contains(expected))
                return true;

    return false;
}

我试图找到 lambda 解决方案，但我找不到。我发现的所有方法都检查 String#equals 而不是 String#contains。

如果有这样的东西就好了:

CollectionsUtils.containsAny(actualList, exptectedList);

但它使用 String#equals 而不是 String#contains 来比较字符串。

编辑:

基于问题:如果 actualList 中的所有子字符串都是 expectedList 的一部分，我想得到 TRUE。下面凯文的解决方案对我有用。

Answer 1

这样的事情怎么样:

list1.stream().allMatch(s1 -> list2.stream().anyMatch(s2 -> s1.contains(s2)))

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• allMatch 将检查所有内容是否为 true
• anyMatch 将检查是否至少有一个为 true

这里有一些类似 Java 7 风格的东西，没有 lambda 和流，可以更好地理解正在发生的事情:

boolean allMatch = true;       // Start allMatch at true
for(String s1 : list1){
  boolean anyMatch = false;    // Start anyMatch at false inside the loop
  for(String s2 : list2){
    anyMatch = s1.contains(s2);// If any contains is true, anyMatch becomes true as well
    if(anyMatch)               // And stop the inner loop as soon as we've found a match
      break;
  }
  allMatch = anyMatch;         // If any anyMatch is false, allMatch becomes false as well
  if(!allMatch)                // And stop the outer loop as soon as we've found a mismatch
    break;
}
return allMatch;

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---

如果您更喜欢CollectionsUtils.containsAny(list1, list2)，您可以在代码的其他地方重复使用，您总是可以自己制作一个:

public final class CollectionsUtil{
  public static boolean containsAny(ArrayList<String> list1, ArrayList<String> list2){
    return list1.stream().allMatch(s1 -> list2.stream().anyMatch(s2 -> s1.contains(s2)));
    // Or the contents of the Java 7 check-method above if you prefer it
  }

  private CollectionsUtil(){
    // Util class, so it's not initializable
  }
}

然后可以根据需要使用:

boolean result = CollectionsUtils.containsAny(actualList, expectedList);

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