javascript - 处理 JSON 以创建子级与父级的层次关系

Question

我在这里得到了类似的答案，但我一直在寻找与此相反的东西，所以我从这个答案中获得帮助来解释我的问题: Process JSON to create the hierarchical relationship

所以，我有这样的原始数据:

{
  "my_data": [
      {
          "name": "bugs_db",
          "type": "database",
          "children": [
              {
                  "name": "oss",
                  "type": "ui"
              },
              {
                  "name": "dashboard",
                  "type": "ui"
              },
              {
                  "name": "dev-dash",
                  "type": "ui"
              }
          ]
      },
      {
          "name": "oss",
          "type": "ui",
          "children": [
              {
                  "name": "active-directory",
                  "type": "nfs"
              },
              {
                  "name": "passive-directory",
                  "type": "FAT32"
              },
              {
                "name": "jira_db",
                "kind": "database"
              }
          ]
      },
      {
          "name": "jira_db",
          "type": "database",
          "children": [
            {
              "name": "oss",
              "kind": "ui"
            },
            {
              "name": "something",
              "kind": "ui"
            }
          ]
      },
      {
          "name": "active_directory",
          "type": "nfs",
          "children": []
      }
  ]
}

我需要处理上面的数据来列出一个 child 的所有 parent ..例如，如果我选择“name”=“oss”，那么层次关系应该是这样的:

{
  "name": "oss",
   "type": "ui",
   "parents": [
     {
        "name": "bugs_db",
        "type": "database",
        "parents": [
        ]
     },
     {
       "name": "jira_db",
       "type": "database"
     }
   ]
}

也可以有一些循环关系.. 例如。 oss 是 bugs_db 的 child ，而 bugs_db 也是 oss 的 child 。在这种情况下，只需进一步跳过并向父对象添加键“circular”:true。我想我可以尝试使用 for 循环进行处理并实现此目的。但我正在寻找此处建议的一些类似解决方案:https://stackoverflow.com/a/50491255

Answer 1

基本上，您可以使用相同的方案来测试循环引用和过滤父项。

function getParents(name, visited = new Set) {
    var item = map.get(name);

    if (!item) {
        return item;
    }

    if (visited.has(name)) {
        return { name, type: item.type, circular: true };
    }

    visited.add(name);

    return {
        name,
        type: item.type,
        parent: object.my_data
            .filter(({ children }) => children.some(o => o.name === name))
            .map(({ name }) => getParents(name, visited))
    };
}

var object = { my_data: [{ name: "bugs_db", type: "database", children: [{ name: "oss", type: "ui" }, { name: "dashboard", type: "ui" }, { name: "dev-dash", type: "ui" }] }, { name: "oss", type: "ui", children: [{ name: "active-directory", type: "nfs" }, { name: "passive-directory", type: "FAT32" }, { name: "jira_db", kind: "database" }] }, { name: "jira_db", type: "database", children: [{ name: "oss", kind: "ui" }, { name: "something", kind: "ui" }] }, { name: "active_directory", type: "nfs", children: [] }] },
    map = new Map(object.my_data.map(o => [o.name, o]));

console.log(getParents("oss"));

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