java - 在哪里以及如何解码@PathVariable

Question

客户端在服务器上发送(实现无关紧要):

/path/items/ + urlencode(id, SOME_ENCODING)

考虑结果 URL 将是:

/path/items/my%2Fkey

因此我在服务器上有:

@RequestMapping(value = "/path/items/{identifier}", method = RequestMethod.GET)
public Item get(@PathVariable String identifier) {
try {
    return DAO.getItemByIdentifier(URLDecoder.decode(identifier, SOME_ENCODING))
}
catch (UnsupportedEncodingException e) {
...
}

有没有办法在Spring内部做到这一点？我的意思是让 identifier 已经解码，所以我可以:

@RequestMapping(value = "/path/items/{identifier}", method = RequestMethod.GET)
    public Item get(@PathVariable String identifier) {
return DAO.getitemByidentifier(identifier); // already decoded!
    }

Answer 1

您可以在 web.xml 中使用 Spring 的 CharacterEncodingFilter 类作为过滤器，如下所示:

<filter>
    <filter-name>CharacterEncodingFilter</filter-name>
    <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
    <init-param>
        <param-name>encoding</param-name>
        <param-value>UTF-8</param-value>
    </init-param>
    <init-param>
        <param-name>forceEncoding</param-name>
        <param-value>true</param-value>
    </init-param>
</filter>
<filter-mapping>
    <filter-name>CharacterEncodingFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>