c# - C#中的组合算法

Question

我需要 n 个字段的组合，其中每个字段可以等于 null 或不等于 null。对于每个组合，字段不能重复。基本上，总共应该有 2^n 种组合。

示例:

如果我有 2 个字段 A 和 B，输出中的组合应该是:

A != null and B != null
A != null and B == null
A == null and B != null
A == null and B == null

如果我有 3 个字段 A、B 和 C，输出中的组合应该是:

A != null and B != null and C != null
A != null and B != null and C == null
A != null and B == null and C != null
A != null and B == null and C == null
A == null and B != null and C != null
A == null and B != null and C == null
A == null and B == null and C != null
A == null and B == null and C == null

我不知道这个组合叫什么，所以我怎么能在字段数是变量的代码中做到这一点？

谢谢!

Answer 1

如果您想要这样的行的 生成器，您可以使用 Linq:

   int count = 2;

   var lines = Enumerable
     .Range(0, 1 << count) // 1 << count == 2 ** count
     .Select(item => String.Join(" and ", Enumerable
       .Range(0, count)
       .Select(index => ((Char) ('A' + index)).ToString() + 
                        ((item >> index) % 2 == 0 ? " != null" : " == null"))));


   // Let's print out all the lines generated
   Console.Write(String.Join(Environment.NewLine, lines));

对于count = 2，输出是

  A != null and B != null
  A == null and B != null
  A != null and B == null
  A == null and B == null

编辑:一个小的修改让您可以输入自己的名字:

  String[] names = new String[] { "A", "B", "C" };

  var lines = Enumerable
    .Range(0, 1 << names.Length) // 1 << count == 2 ** count
    .Select(item => String.Join(" and ", Enumerable
       .Range(0, names.Length)
       .Select(index => names[index] +
                        ((item >> index) % 2 == 0 ? " != null" : " == null"))));

  // Let's print out all the lines generated
  Console.Write(String.Join(Environment.NewLine, lines));