javascript - 返回发行专辑最多的年份的函数

Question

以下是甲壳虫乐队发行年份的专辑列表。编写一个返回年份的函数大多数专辑发行。如果有一年，返回一个字符串，否则返回一个数组。

var beatles_discography = {
 "Please Please Me": 1963,
 "With the Beatles": 1963,
 "A Hard Day's Night ": 1964, 
 "Beatles for Sale ": 1964, 
 "Twist and Shout ": 1964, 
 "Help ": 1965, 
 "Rubber Soul ": 1965,
 "Revolver": 1966,
 "Sgt. Pepper's Lonely Hearts Club Band": 1967,
 "Magical Mystery Tour ": 1967, 
 "The Beatles ": 1968, 
 "Yellow Submarine ": 1969 ,
 "Abbey Road": 1969, 
 "Let It Be ": 1970
}

到目前为止，我试着喜欢这个:-

var x = {
 "Please Please Me": 1963,
 "With the Beatles": 1963,
 "A Hard Day's Night ": 1964, 
 "Beatles for Sale ": 1964, 
 "Twist and Shout ": 1964, 
 "Help ": 1965, 
 "Rubber Soul ": 1965,
 "Revolver": 1966,
 "Sgt. Pepper's Lonely Hearts Club Band": 1967,
 "Magical Mystery Tour ": 1967, 
 "The Beatles ": 1968, 
 "Yellow Submarine ": 1969 ,
 "Abbey Road": 1969, 
 "Let It Be ": 1970
}
var y = {};

for (var key in x){
  y[x[key]] = y[x[key]] ? y[x[key]] + 1: 1;
}
var arr = Object.keys(y);
function getYear(arr){
  for (var m=0; m<arr.length -1; m++){
  if(y[arr[0]] > y[arr[1]]){
    return arr[0];
  }else{
    var temp = [];
    if(y[m] == y[m+1]){
      temp.push(arr[m],arr[m+1]);
    }
    return temp;
  }
  }
}

console.log(getYear(arr));

此代码的预期输出是 1964，因为在列表中我今年只重复了 3 次。如果在对象中我也有 1965 3 次，那么我需要返回一个像 [1964, 1965] 这样的数组。感谢您的帮助。

Answer 1

var albums = {
    "Please Please Me": 1963,
    "With the Beatles": 1963,
    "A Hard Day's Night ": 1964,
    "Beatles for Sale ": 1964,
    "Twist and Shout ": 1964,
    "Help ": 1963,
    "Rubber Soul ": 1965,
    "Revolver": 1966,
    "Sgt. Pepper's Lonely Hearts Club Band": 1967,
    "Magical Mystery Tour ": 1967,
    "The Beatles ": 1968,
    "Yellow Submarine ": 1969,
    "Abbey Road": 1969,
    "Let It Be ": 1970
}


function getYear(albums) {
    var albumOccurrence = {};
    var max = 0;
    var res = [];
    for (var key in albums) {
        albumOccurrence[albums[key]] = albumOccurrence[albums[key]] ? albumOccurrence[albums[key]] + 1 : 1;
        if (albumOccurrence[albums[key]] > max)
            max = albumOccurrence[albums[key]];
    }
    console.log(max, albumOccurence);
    for (var occurrence in albumOccurrence) {
        if (albumOccurrence[occurrence] == max) {
            res.push(occurrence);
        }
    }
    if (res.length == 1) {
        res = res[0];
    }
    return res;
}
console.log(getYear(albums));

这是你要找的吗？