python - 在 Python 中查找列表的限制

Question

我将以下 2 个列表相互映射:

Values =[1,2,3,4,5,6,8,9,10,9,7,6,5.50,5,6,7,8,10,12,15,14 ,13.50 12]
Dates =[Day1,Day2,Day3,Day4,Day5,Day6,Day8,Day9,Day10,Day11,..,Day20]

正如您在屏幕截图中看到的那样

我想编写一个程序来循环遍历列表值并返回值

XA= [X,A]
AB= [A,B]
BC=[B,C]
CD= [C,D]
DE=[D,E]

挑战是我不知道列表是否只包含从 X 到 D 的值，还是会一直持续到 N

我已经尝试使用下面的代码，但结果并没有给我想要的结果，因为我需要在继续该过程之前找出一种存储值的方法:

for Prs in close:


    # getung the high


    if Prs > SwingHigh:
        SwingHigh = Prs
        Swinglow=Prs


    elif Prs < Swinglow:
        Swinglow = Prs
        PrevHigh=SwingHigh

    else:
        PrevLow=Swinglow



    impulSizee = SwingHigh - InicialPrice
    retrSize = SwingHigh - Swinglow



    # geting the index if the lows low

    print('-------------------------------------')
    print('theprice testing',Prs)
    print('the starting price is InicialPrice ',InicialPrice)
    print('the swing low is PrevLow ',PrevLow)
    print('the swing hige is PrevHigh',PrevHigh)
    print('the new high SwingHigh ',SwingHigh)
    print('the new low Swinglow------ ',Swinglow)

Answer 1

结合使用 pandas shift + cumsum 技巧和 groupby:

s = pd.Series(values)
v = s.gt(s.shift(-1))
[g.tolist() for _, g in s.groupby(v.ne(v.shift()).cumsum())]

[[1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 8.0, 9.0],   # XA
 [10.0, 9.0, 7.0, 6.0, 5.5],                 # AB
 [5.0, 6.0, 7.0, 8.0, 10.0, 12.0],           # BC
 [15.0, 14.0, 13.5],                         # CD
 [12.0]]                                     # DE