python - 在 Python 中生成给定游戏列表的可能组合

Question

我想从给定的游戏列表中生成可能性的总数，例如 ['France - Germany'。这样，在这种情况下，总结果将是 3 种可能的结果{要么主队获胜，他们平局，要么客队获胜}。

• 可能的结果是 3

1   FRANCE - GERMANY 12   FRANCE - GERMANY x3   FRANCE - GERMANY 2

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And for another case where the list is ['France - Germany', 'Spain - Italia']

• Possible number of outcomes are 9

1FRANCE - GERMANY 1SPAIN - ITALIA 1 2   FRANCE - GERMANY 1SPAIN - ITALIA x 3   FRANCE - GERMANY 1SPAIN - ITALIA 24   FRANCE - GERMANY xSPAIN - ITALIA 15   FRANCE - GERMANY xSPAIN - ITALIA x6   FRANCE - GERMANY xSPAIN - ITALIA 27   FRANCE - GERMANY 2SPAIN - ITALIA 18   FRANCE - GERMANY 2SPAIN - ITALIA x9   FRANCE - GERMANY 2SPAIN - ITALIA 2

The Following is my code

import itertools

games = ['France - Germany']
case = ["1","X","2"]
results = []
for eachcase in case:
    for game in games:
        results.append("%s %s" % (game, eachcase))


print("\n".join(results)+ "\n %s" %len(results))

列表中项目的输出是

France - Germany 1
France - Germany X
France - Germany 2

这很好，但随着列表项目数量的增加，它不起作用。在此先感谢您对解决此问题的任何帮助:)

Answer 1

您可以使用列表理解轻松地做到这一点:

fg = [ ("FRANCE-GERMANY",outcome) for outcome in (1,"x",2) ]
for g1 in fg: print(g1)
print("")

si = [ ("SPAIN-ITALY",outcome) for outcome in (1,"x",2) ]
final = [ (g1,g2) for g1 in fg for g2 in si ]
for g1,g2 in final:
    print(g1)
    print(g2)
    print("")

如果你想要一个更通用的方法，itertools 模块中的 product 函数也可以提供帮助:

from itertools import product
fg    = list(product(["FRANCE-GERMANY"],(1,"x",2)))
si    = list(product(["SPAIN-ITALY"],(1,"x",2)))
final = list(product(fg,si))