objective-c - 在 NSArray 中搜索对象属性的快速方法

Question

我有一个自定义对象的 NSArray，它们都具有 NSString 类型的@property name。如何快速枚举数组并创建一个新数组，其中仅包含在其 name 属性中具有特定单词的对象？

例如:

CustomObject *firstObject = [[CustomObject alloc] init];
firstObject.name = @"dog";

CustomObject *secondObject = [[CustomObject alloc] init];
secondObject.name = @"cat";

CustomObject *thirdObject = [[CustomObject alloc] init];
thirdObject.name = @"dogs are fun";

NSMutableArray *testArray = [NSMutableArray arrayWithObjects:firstObject,
                                                             secondObject,
                                                             thirdObject, 
                                                             nil];

// I want to create a new array that contains all objects that have the word 
// "dog" in their name property. 

我知道我可以像这样使用 for 循环:

NSMutableArray *newArray = [NSMutableArray array];
for (CustomObject *obj in testArray)
{
    if ([obj.name rangeOfString:@"dog"].location == NSNotFound) {
        //string wasn't found
    }

    else {
        [newArray addObject:obj];
    }
}

但是有没有更有效的方法呢？谢谢!

Answer 1

NSString *searchString = @"dog";
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.name contains %@", searchString];
NSArray *filteredArray = [testArray filteredArrayUsingPredicate:predicate];