java - 这是一个无限循环吗？我究竟做错了什么？ (Java 方法)

Question

我应该编写一个“bisquare”方法，返回一个数字范围内的 bisquare 的数量。我以为我已经弄明白了，但是当我运行这段代码时，没有任何显示，我的笔记本电脑开始像疯了一样嗡嗡作响。系统从不说它完成了。

这是我的代码。我究竟做错了什么？ (如果我没有正确设置它，我也在寻找解决问题的方法。)

   // An integer that is the sum of the squares of two other integers is called bisquare
   // 5 is bisquare because it is 1*1 + 2*2
   // 4 is bisquare because it is 0*0 + 2*2  (we can use 0 as one of our numbers)
   // 8 is bisquare because it is 2*2 + 2*2  (we can use the same two numbers)
   // 3 is not bisquare, 6 is not bisquare
   //  
   // Given two int parameters, low and high, return the number of bisquares that
   // fall between low and high (inclusive)
   // 
   // EXAMPLES:
   // low = 1, high = 6
   // return 4
   // 1, 2, 4, and 5 are bisquare.  3 and 6 are not
   //
   // low = 7, high = 7
   // return 0
   // 7 is not bisquare.  that is the entire range we are checking. 

   public static int bisquare(int low, int high)
   {      
      int count = 0;
      boolean isBisquare = false;
      for (int checkNum = low; checkNum < high; checkNum++) {
         while (!isBisquare) {
            for (int i = 0; i < high; i++) {
               for (int j = 0; j < high; j++) {
                  if ((i*i) + (j*j) == low) {
                     count++;
                     isBisquare = true;
                  }
               }
            }   
         }
      }
      return count;
   }

Answer 1

是的，如果 (i*i) + (j*j) == low 中没有一个计算结果为真，则 while 将无限循环。