java - 没有找到类 org.json.JSONObject 的序列化器，也没有发现创建 BeanSerializer 的属性

Question

从 Web 服务获取 JSON，Json 数组作为响应

   [3]
   0:  {
   id: 2
  name: "a561137"
    password: "test"
  firstName: "abhishek"
   lastName: "ringsia"
    organization: "bbb"
      }-
    1:  {
      id: 3
  name: "a561023"
password: "hello"
     firstName: "hello"
   lastName: "hello"
     organization: "hello"
   }-
 2:  {
  id: 4
  name: "a541234"
  password: "hello"
 firstName: "hello"
  lastName: "hello"
  organization: "hello"
    }

在 JsonArray 中获取响应后读取 Json 数组的 Json 对象时出错:

List<User> list = new ArrayList<User>();
JSONArray jsonArr = new JSONArray(response);

for (int i = 0; i < jsonArr.length(); i++) {
    JSONObject jsonObj = jsonArr.getJSONObject(i);
    ObjectMapper mapper = new ObjectMapper();
    User usr=   mapper.convertValue(jsonObj, User.class);
    list.add(usr);
}

No serializer found for class org.json.JSONObject and no properties discovered to create BeanSerializer (to avoid exception, disable SerializationConfig.Feature.FAIL_ON_EMPTY_BEANS) )

Answer 1

必须首先接受它作为一个 Json 数组，然后在读取它的对象时必须使用 Object Mapper.readValue ，因为 Json 对象仍然在字符串中。

List<User> list = new ArrayList<User>();
JSONArray jsonArr = new JSONArray(response);

for (int i = 0; i < jsonArr.length(); i++) {
    JSONObject jsonObj = jsonArr.getJSONObject(i);
    ObjectMapper mapper = new ObjectMapper();
    User usr = mapper.readValue(jsonObj.toString(), User.class);      
    list.add(usr);
}