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java - Nashorn,Java 集合,如何在纯 javascript 中实现 equals 和 hashCode

转载 作者:塔克拉玛干 更新时间:2023-11-03 03:50:11 25 4
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我遇到了以下问题。我想在 Nashorn 脚本中使用 java.util.HashMapjava.util.PriorityQueue,我需要在其中使用特定的自定义对象作为 HashMap 中的 ,并使用 HashMap.containsKey() 检查 Map 中是否有键(另一种选择是检查对象是否在Collection.contains(Object o)).

因此,显然,我需要根据某些字段值在我的对象中实现 equals 和 hashCode。

例如:

  1. 尝试使用 JavaScript。不起作用,因为 JavaScript 没有这些方法。请参阅示例 1示例 2

  2. 扩展 java.lang.Object。 示例 3。部分工作,正在调用方法。但是

    • 如何插入带有参数的构造函数?
    • 如何将 this:[object Object] 转换为 other:jdk.nashorn.javaadapters.java.lang.Object@0,反之亦然?
  3. 在 Java 中实现我的自定义类并在 JavaScript 中扩展它。 示例 4。作品。但是,如果我必须使用 Java,是否需要 Nashorn?

var PriorityQueue = java.util.PriorityQueue;
var HashMap = java.util.HashMap;
var Integer = java.lang.Integer;

// Sample 1
// Doesn't work, equals and hashCode are not being invoked
function Vertex1(from, cost) {
this.from = from;
this.cost = cost;

this.equals = function(other) { return this.from == other.from; }
this.hashCode = function() { return Integer.hashCode(this.from); }
}

var hm = new HashMap();
hm.put(new Vertex1(1, 10), 10);
hm.put(new Vertex1(1, 20), 21);
// Prints size is 2, but I'd like to see 1
print("HashMap size: " + hm.size());
// Prints false
print("HashMap1 contains: " + hm.containsKey(new Vertex1(1, 20)));

// ------------------------------------------------------------------
// Sample 2
// Doesn't work, equals and hashCode are not being invoked
function Vertex1(from, cost) {
this.from = from;
this.cost = cost;
}
Vertex1.prototype = {
equals : function(other) { return this.from == other.from; },
hashCode : function() { return Integer.hashCode(this.from); },
}
var hm = new HashMap();
hm.put(new Vertex1(1, 10), 10);
hm.put(new Vertex1(1, 20), 21);
// Prints size is 2, but I'd like to see 1
print("HashMap size: " + hm.size());
// Prints false
print("HashMap1 contains: " + hm.containsKey(new Vertex1(1, 20)));

// ------------------------------------------------------------------
// Sample 3
// Works partially, Methods are being invoked. But

// 1. How to plugin construstor with parameters?
// 2. How to do the cast from this:[object Object] to other:jdk.nashorn.javaadapters.java.lang.Object@0, or vice versa

var JObject = Java.type("java.lang.Object");
var Vertex2 = Java.extend(JObject, {
from : 0,
equals : function(other) { return this.from.equals(other.from); },
hashCode : function() { return Integer.hashCode(this.from); },
});
var hm = new HashMap();
// How to implement constructor for new Vertex2(10, 10)?
hm.put(new Vertex2(), 10);
hm.put(new Vertex2(), 21);
// Prints size is 2, because hashCode is the same and equals returns false
print("HashMap size: " + hm.size());
// Prints false, because equals returns false
print("HashMap1 contains: " + hm.containsKey(new Vertex2()));

// ------------------------------------------------------------------
// Sample 4
// com.arsenyko.MyObject is implemented in Java, Works, but Nashorn is ambiguous then!!!
var MyObject = Java.type("com.arsenyko.MyObject");
var Vertex2 = Java.extend(MyObject, {});
var hm = new HashMap();
hm.put(new Vertex2(1, 10), 10);
hm.put(new Vertex2(1, 20), 21);
print("HashMap size: " + hm.size());
print("HashMap1 contains: " + hm.containsKey(new Vertex2(1, 10)));

编辑 1

@Tomasz,谢谢。已经看到所有提到的链接。但是尽管存在一些未记录的内容。差点放弃 Nashorn。得出以下部分解决方案,正在调用方法,正在使用构造函数,但是如何在equals方法中强制转换other.from以获得访问到原始对象的 from 字段(此代码为 Vertex 的每个实例生成不同的类):

//load("nashorn:mozilla_compat.js");
var PriorityQueue = java.util.PriorityQueue;
var HashMap = java.util.HashMap;
var Integer = java.lang.Integer;

function Vertex1(from, cost) {
this.from = from;
this.cost = cost;

this.equals = function(other) {
var value1 = this.from;
// How to get other.from here???
var value2 = other.from;
print('value1=' + value1 + ' value2=' + value2);
print(other);
var eq = value1.equals(value2);
print('equals is ' + eq);
return eq;
}
this.hashCode = function() {
var hashCode = Integer.hashCode(this.from);
print('hashCode is ' + hashCode);
return hashCode;
}

var JObject = Java.type("java.lang.Object");
// return Java.extend(JObject, this); // doesn't work
// return this; // doesn't work
// return new JavaAdapter(java.lang.Object, this); // Works! with load("nashorn:mozilla_compat.js");
var Type = Java.extend.apply(Java, [JObject]);
return new Type(this);
}

var hm = new HashMap();
hm.put(new Vertex1(1, 10), 10);
hm.put(new Vertex1(1, 20), 21);
// Prints size is 2, but I'd like to see 1
print("HashMap size: " + hm.size());
// Prints false
print("HashMap contains: " + hm.containsKey(new Vertex1(1, 20)));

编辑 2

感谢 Tomasz,正如他所指出的,每次使用特定于类的实现对象调用 Java.extend() 函数都会生成一个新的 Java 适配器类。因此,我们需要一个 Object Extender 并使用该类型实例化对象,正如他在示例中所展示的那样。我对其进行了一些修改,因此它使用工厂或直接构造函数生成具有相同类的实例,因为我们使用的是相同的 Object Extender

var HashMap = java.util.HashMap;
var JInteger = java.lang.Integer;
var JObject = Java.extend(java.lang.Object);

var createVertex = (function() {
var
_equals = function(other) {
print(this + ' vs ' + other);
return this._from === other.from;
};
_hashCode = function() {
var hashCode = JInteger.hashCode(this._from);
print(hashCode);
return hashCode;
};
return function(from, cost) {
return new JObject() {
_from : from,
_cost : cost,
equals : _equals,
hashCode : _hashCode,
}
}
})();

var JSVertex = function(from, cost) {
return new JObject() {
_from : from,
_cost : cost,
equals : function(other) {
print(this + ' vs ' + other);
return this._from === other._from;
},
hashCode : function() {
var hashCode = JInteger.hashCode(this._from);
print(hashCode);
return hashCode;
}
}
}

var v1 = JSVertex(1, 10);
var v2 = JSVertex(1, 20);
//var v1 = createVertex(1, 10);
//var v2 = createVertex(1, 20);
var v3 = createVertex(1, 20);
print(v1.class === v2.class); // returns true
print(v2.class === v3.class); // returns true
var hm = new HashMap();
hm.put(v1, 10);
hm.put(v2, 21);
print("HashMap size: " + hm.size()); // Prints 2, but I'd like to see 1
print("HashMap contains: " + hm.containsKey(v3)); // Prints false

但是还有一个问题,equals的参数类型是jdk.nashorn.javaadapters.java.lang.Object,也就是说equals 中的 otherthis 是不同的类型。 有没有办法从传递给 equals 的对象中转换或获取 _from 值?

解决方案

在 Tomasz 的回答中查看问题的解决方案

Tomasz 干得好!谢谢。

PS:很遗憾,在 Nashorn 中没有简洁明了的方法来实现 equalshashCode。这对于原型(prototype)制作很有用。只需将其与此进行比较 :)

import groovy.transform.EqualsAndHashCode
@EqualsAndHashCode(excludes="cost")
class Vertex {
int from, cost
}

最佳答案

在 Rhino 中你会使用:

var vertex = new JavaAdapter(java.lang.Object, new Vertex(1, 10));
hm.put(vertex, 10);

使 JavaScript 方法覆盖 java.lang.Object 中相同命名的 Java 方法(参见引用资料 https://developer.mozilla.org/en-US/docs/Mozilla/Projects/Rhino/Scripting_Java#The_JavaAdapter_Constructor)

也许 Nashorn 中有类似的构造。

编辑:

您可以在 Nashorn 中使用 Rhino 语法。只需放行:

load("nashorn:mozilla_compat.js");

参见:https://wiki.openjdk.java.net/display/Nashorn/Rhino+Migration+Guide

编辑:(再次)

使用 Nashorn 似乎要复杂得多:

// we will need a factory method
var createVertex = (function() { // i hope you are familiar with "inline" function calls

// private variables used in every call of factory method - but initialized once
var
JObjExtender = Java.extend(Java.type("java.lang.Object")),
JInteger = Java.type("java.lang.Integer"),
_equals = function(other) {
return this.from === other.from;
},
_hashCode = function() {
return JInteger.hashCode(+this.from); // leading "+" converts to number
};

// the "actual" factory method
return function(from, cost) {
return new JObjExtender() {
from : from,
cost : cost,
equals : _equals,
hashCode : _hashCode
};
};
})();

var vertex = createVertex(1, 10);
hm.put(vertex, 10);

http://docs.oracle.com/javase/8/docs/technotes/guides/scripting/prog_guide/javascript.html

更有趣的是,如果您创建多个实例,如下所示:

var v1 = createVertex(1, 10);
var v2 = createVertex(1, 20);

然后它们属于同一类(我希望它们是 Object 的两个匿名太阳类的实例)。

var classEquals = (v1.class === v2.class); // produces : true

一个技巧:

尽管在 Nashorn 中你不能像这样动态地扩展非抽象类:

var v1 = new java.lang.Object(new JSVertex(10, 10));
// produces: TypeError: Can not construct java.lang.Object with the passed
// arguments; they do not match any of its constructor signatures.

您可以用这种方式扩展任何抽象类或接口(interface)。 (因为任何实现接口(interface)的匿名类也会扩展 Object,所以您也可以覆盖 equalshashCode 方法)。

为了说明这一点,假设您有一个 JavaScript“原型(prototype)类”:

var JSVertex = function (from, cost) {
this.from = from;
this.cost = cost;
};
JSVertex.prototype = {
equals : function(other) {
return this.from === other.from;
},
hashCode : function() {
return java.lang.Integer.hashCode(+this.from); // leading "+" converts to number
},
compare : function(other) {
return this.from - (+other.from);
}
};

现在您可以创建其“Java 封装”实例,如下所示:

var v1 = new java.lang.Comparable(new JSVertex(10, 10));
print(v1.class);
// produces both: class jdk.nashorn.javaadapters.java.lang.Object and
// class jdk.nashorn.javaadapters.java.lang.Comparable

var v2 = new java.lang.Comparable(new JSVertex(11, 12));
print(v2 instanceof java.lang.Object); // produces true
print(v2 instanceof java.lang.Comparable); // produces true

知道您可以创建一个空的 Java 接口(interface)来启用此类包装器,而无需提供额外的方法实现(如上面示例中的 CompareComparable) .

问题

正如您所指出的,以上述两种方式创建的对象都是具有固定“接口(interface)”的 Java 对象。因此,任何来自包装的 JavaScript 对象的方法或字段,如果没有被实现的接口(interface)或类明确指定,将无法从 javascript 访问。

解决方案

经过一些摆弄,我找到了上述问题的解决方案。它的关键是来自 Nashorn 脚本 API 的 jdk.nashorn.api.scripting.AbstractJSObject 类。

考虑我们有 JSVertex“javascript 类”(与上面已经介绍的非常相似):

var JSVertex = function (from, cost) {
this.from = +from;
this.cost = +cost;
};
JSVertex.prototype = {
equals : function(other) {
print("[JSVertex.prototype.equals " + this + "]");
return this.from === other.from;
},
hashCode : function() {
var hash = java.lang.Integer.hashCode(this.from);
print("[JSVertex.prototype.hashCode " + this + " : " + hash + "]");
return hash;
},
toString : function() {
return "[object JSVertex(from: " +
this.from + ", cost: " + this.cost + ")]";
},
// this is a custom method not defined in any Java class or Interface
calculate : function(to) {
return Math.abs(+to - this.from) * this.cost;
}
};

让我们创建一个函数,它允许我们以这种方式将 Java 对象包装在任何 JavaScript 对象上,JavaScript 对象中的任何同名方法都将“扩展”相应的 Java 对象方法。

var wrapJso = (function() { 

var
JObjExtender = Java.extend(Java.type(
"jdk.nashorn.api.scripting.AbstractJSObject")),
_getMember = function(name) {
return this.jso[name];
},
_setMember = function(name, value) {
this.jso[name] = value;
},
_toString = function() {
return this.jso.toString();
};

return function(jsObject) {
var F = function() {};
F.prototype = jsObject;
var f = new F();
f.jso = jsObject;
f.getMember = _getMember;
f.setMember = _setMember;
f.toString = _toString; // "toString hack" - explained later
return new JObjExtender(f);
};
})();

终于写完了,让我们看看它的工作。

在 JSVertex 对象上创建一个包装器并对其进行一些测试:

var wrapped = wrapJso(new JSVertex(11,12));

// access custom js property and method not defined in any java class
// or interface.
print(wrapped.from);
print(wrapped.calculate(17));

print("--------------");

// call toString() and hashCode() from JavaScript on wrapper object
print(wrapped.toString());
print(wrapped.hashCode());

print("--------------");

// Use StringBuilder to make Java call toString() on our wrapper object.
print(new java.lang.StringBuilder().append(wrapped).toString() );
// see hack in wrapJso() - for some reason java does not see
// overriden toString if it is defined as prototype member.

// Do some operations on HashMap to get hashCode() mehod called from java
var map = new java.util.HashMap();
map.put(wrapped, 10);
map.get(wrapped);

wrapped.from = 77;
map.get(wrapped);

print("--------------");

// let's show that modyfing any of pair: wrapped or jso touches underlying jso.
var jso = new JSVertex(17,128);
wrapped = wrapJso(jso);
print(wrapped);
jso.from = 9;
wrapped.cost = 10;
print(wrapped);
print(jso);
print(jso == wrapped);

输出:

11
72
--------------
[object JSVertex(from: 11, cost: 12)]
[JSVertex.prototype.hashCode [object JSVertex(from: 11, cost: 12)] : 11]
11
--------------
[object JSVertex(from: 11, cost: 12)]
[JSVertex.prototype.hashCode [object JSVertex(from: 11, cost: 12)] : 11]
[JSVertex.prototype.hashCode [object JSVertex(from: 11, cost: 12)] : 11]
[JSVertex.prototype.hashCode [object JSVertex(from: 77, cost: 12)] : 77]
--------------
[object JSVertex(from: 17, cost: 128)]
[object JSVertex(from: 9, cost: 10)]
[object JSVertex(from: 9, cost: 10)]
false

关于java - Nashorn,Java 集合,如何在纯 javascript 中实现 equals 和 hashCode,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25379340/

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