java - 为什么 servlet 不检索该部分？它显示 null 作为文件名

Question

html 片段向名为 servlet 的 servlet 发送一个 post 请求。请求的类型为 multipart/form-data。但 servlet 什么也没找到，并打印 null 作为我尝试检索的部分的名称。这是为什么 ？

<form method="post" action="servlet" enctype="multipart/form-data">
        <input type="file" value="browse" name="FileShared" />
        <input type="submit" value="submit" />
 </form>

---

import javax.servlet.http.Part;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

    @Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
    response.setContentType("text/plain");
    //String fileName = request.getPart("FileShared").getName(); 
    // Throws a nullpointer exception if I don't comment the above statement
    PrintWriter writer = response.getWriter();
    //writer.println(fileName);
    Collection<Part> c = request.getParts();
    Iterator i = c.iterator();
    while(i.hasNext()) {
        writer.println("Inside while loop"); // This statement never gets printed
        writer.println(i.next());
    }
    writer.println("outside while loop"); // Only this statement gets printed
}

Answer 1

如果您想使用 Servlet 3.0 HttpServletRequest#getParts() 方法，那么您必须使用 @MultipartConfig 注释您的 servlet。

示例:

@WebServlet(urlPatterns={"/SampleServlet"})
@MultipartConfig
public class SampleServlet extends HttpServlet {

}