java - 格式化 Web 服务响应

Question

我使用以下函数来检索网络服务响应:

private String getSoapResponse (String url, String host, String encoding, String soapAction, String soapRequest) throws MalformedURLException, IOException, Exception {         
    URL wsUrl = new URL(url);     
    URLConnection connection = wsUrl.openConnection();     
    HttpURLConnection httpConn = (HttpURLConnection)connection;     
    ByteArrayOutputStream bout = new ByteArrayOutputStream(); 

    byte[] buffer = new byte[soapRequest.length()];     
    buffer = soapRequest.getBytes();     
    bout.write(buffer);     
    byte[] b = bout.toByteArray();          

    httpConn.setRequestMethod("POST");
    httpConn.setRequestProperty("Host", host);

    if (encoding == null || encoding == "")
        encoding = UTF8;

    httpConn.setRequestProperty("Content-Type", "text/xml; charset=" + encoding);
    httpConn.setRequestProperty("Content-Length", String.valueOf(b.length));
    httpConn.setRequestProperty("SOAPAction", soapAction);

    httpConn.setDoOutput(true);
    httpConn.setDoInput(true);

    OutputStream out = httpConn.getOutputStream();
    out.write(b); 
    out.close();

    InputStreamReader is = new InputStreamReader(httpConn.getInputStream());
    StringBuilder sb = new StringBuilder();
    BufferedReader br = new BufferedReader(is);
    String read = br.readLine();

    while(read != null) {
        sb.append(read);
        read = br.readLine();
    }

    String response = decodeHtmlEntityCharacters(sb.toString());    

    return response = decodeHtmlEntityCharacters(response);
}

但我对这段代码的问题是它返回了很多特殊字符并使 XML 的结构无效。
响应示例:

<PLANT>A565</PLANT>
          <PLANT>A567</PLANT>
          <PLANT>A585</PLANT>
          <PLANT>A921</PLANT>
          <PLANT>A938</PLANT>
        </PLANT_GROUP>
      </KPI_PLANT_GROUP_KEYWORD>
      <MSU_CUSTOMERS/>
    </DU>
    <DU> 

所以为了解决这个问题，我使用下面的方法并传递整个响应，用相应的标点符号替换所有特殊字符。

private final static Hashtable htmlEntitiesTable = new Hashtable();
static {
    htmlEntitiesTable.put("&","&");
    htmlEntitiesTable.put(""","\"");
    htmlEntitiesTable.put("&lt;","<");
    htmlEntitiesTable.put("&gt;",">");  
}

private String decodeHtmlEntityCharacters(String inputString) throws Exception {
    Enumeration en = htmlEntitiesTable.keys();

    while(en.hasMoreElements()){
        String key = (String)en.nextElement();
        String val = (String)htmlEntitiesTable.get(key);

        inputString = inputString.replaceAll(key, val);
    }

    return inputString;
}

但是另一个问题出现了。如果响应包含此段 <VALUE>< 0.5 </VALUE<如果这将通过该方法进行评估，则输出将是:

<VALUE>< 0.5</VALUE>

这使得 XML 的结构再次无效。数据是正确且有效的“< 0.5”，但将其包含在 VALUE 元素中会导致 XML 结构出现问题。

你能帮忙解决这个问题吗？也许我获得或建立响应的方式可以改进。有没有更好的方法来调用 Web 服务并从中获取响应？

如何处理包含“<”或“>”的元素？

Answer 1

你知道如何使用第三方开源库吗？

您应该尝试使用 apache commons-lang:

StringEscapeUtils.unescapeXml(xml)

以下堆栈溢出帖子中提供了更多详细信息:

how to unescape XML in java

文档:

http://commons.apache.org/proper/commons-lang/javadocs/api-release/index.html http://commons.apache.org/proper/commons-lang/userguide.html#lang3 .